Author 
Message 
TAGS:

Hide Tags

Director
Joined: 03 Sep 2006
Posts: 839

At RW Press, the advertising rate, a, is inversely [#permalink]
Show Tags
Updated on: 24 Oct 2012, 05:20
Question Stats:
39% (02:05) correct 61% (02:10) wrong based on 251 sessions
HideShow timer Statistics
At RW Press, the advertising rate, a, is inversely proportional to the productivity measure, b, which, in turn, is inversely proportional to the labor cost, c. Is the labor cost at least 200 when the productivity measure is at least 100? (1) When \(C\geq{100}\), \(B\geq{50}\) (2) When \(C=100\), \(a=100\)
Official Answer and Stats are available only to registered users. Register/ Login.
Originally posted by LM on 24 Oct 2012, 04:46.
Last edited by Bunuel on 24 Oct 2012, 05:20, edited 1 time in total.
Renamed the topic and edited the question.



Director
Joined: 25 Apr 2012
Posts: 701
Location: India
GPA: 3.21
WE: Business Development (Other)

Re: At RW Press, the advertising rate, a, is inversely [#permalink]
Show Tags
31 Oct 2012, 06:22
LM wrote: At RW Press, the advertising rate, a, is inversely proportional to the productivity measure, b, which, in turn, is inversely proportional to the labor cost, c. Is the labor cost at least 200 when the productivity measure is at least 100?
(1) When \(C\geq{100}\), \(B\geq{50}\)
(2) When \(C=100\), \(a=100\) Hi, Based on Q's we can say that a=k1/b where K1 is a constant and a A.R and b is Productivity > Eq 1 b=K2/C where K2 is constant C is labour cost> Eq 2 As per St 1 When C>/100, B>/50 > When C =100, B=50, Value of K2 is 5000 Putting B value as 100 in Eq 2, we can find value of C St 2 Solving in similar way, we end up only with ratio of K1/K2 and hence cannot find value of C against given value of B My ans choice is A
_________________
“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”



Intern
Status: Currently Preparing the GMAT
Joined: 15 Feb 2013
Posts: 29
Location: United States
GPA: 3.7
WE: Analyst (Consulting)

Re: At RW Press, the advertising rate, a, is inversely [#permalink]
Show Tags
08 May 2013, 01:13
Until the OA is posted, this answer will be based on my own understanding, therefore susceptible to be incorrect. The wording of this problem seems off to me. Anyway, let's solve this. First of all, we need to understand and rephrase the problem. We are told that the advetising rate "a" is inversely proportional to the productivity measure "b". Algebraically it means that there's a constant C such as : \(a=\frac{C}{b}\) (1) Likewise, we are told that the productivity measure "b" is inversely proportional to the labor cost "c". Algebraically it means that there's a constant D such as : \(b = \frac{D}{c}\) (2) So we're told that to see whether the labor cost is at least 200 when the productivity measure is at least 100. Meaning that we need to find the value of the constant D. Statement 1 : when\(c >=100\) then \(b >=50\) Using equation (2), we get : \(D = b*c\) which means that given the statement, \(D >= 5000\). If we consider the lowest possible value of D, i.e 5000, we get for \(b >= 100\), \(\frac{D}{c} >= 100\), meaning that \(\frac{5000}{c} >=100\), therefore \(c <= 50\). Which means that the labor cost will be at most 50 when the productivity measure is at least 100 given \(D = 5000\). In fact the more D increases, the more c decreases. So statement 1 is sufficient. Statement 2 : when \(c = 100\) then \(a = 100\) Since a and c are not directly linked, then using both equations 1 & 2, we can find the link between the two variables : We have : \(a=\frac{C}{b}\) and \(b = \frac{D}{c}\) Therefore, by putting b's expression in a, we get \(a = c*\frac{C}{D}\) Since a = c, then we get C = D. And since there's no further information to be gained from this statement (remember that we're looking for D's value), then this statement is insufficient. The final answer is A.Hope that helped



Manager
Joined: 25 Oct 2013
Posts: 160

Re: At RW Press, the advertising rate, a, is inversely [#permalink]
Show Tags
06 Feb 2014, 02:32
My approach was very simple. If two variables are inversely proportional, it simply means if one goes up then other goes down and vice versa. Stmt 1 then gives straight forward NO answer to our question. when C>=100 B>=50. If B increases to 100 then C decreases further and will be <100. Hence C cannot be >=200 when B>=100. Sufficient.Stmt 2 Is a bit tricky. Nothing is mentioned about B and we just know the relation between a & b. b & c. given a=100 and c=100. Now if a goes up b comes down. thus c increases. if b were 900, increasing a & c to >=200 may have b at 400 or 100. we don't know. hence insufficient.A is the answer.
_________________
Click on Kudos if you liked the post!
Practice makes Perfect.



Intern
Joined: 04 Mar 2015
Posts: 23

At RW Press, the advertising rate, a, is inversely proportional to the [#permalink]
Show Tags
15 Apr 2015, 05:27
At RW Press, the advertising rate, a, is inversely proportional to the productivity measure, b, which, in turn, is inversely proportional to the labor cost, c. Is the labor cost at least 200 when the productivity measure is at least 100?
(1) When c=>100, b=>50.
(2) When c=100, a=100.
what I struggled with the question
I think the correct choice should have been E because,
let's take c= 1000 and b=50, then if b= 100; c=500 that is greater than 200 let's take c= 100 and b=50, then if b= 100; c=50 that is less than 200, this inconsistency make the first stament insufficient.
Also, both together are not sufficient.



Math Expert
Joined: 02 Sep 2009
Posts: 47038

Re: At RW Press, the advertising rate, a, is inversely [#permalink]
Show Tags
15 Apr 2015, 05:51
Takoz89 wrote: At RW Press, the advertising rate, a, is inversely proportional to the productivity measure, b, which, in turn, is inversely proportional to the labor cost, c. Is the labor cost at least 200 when the productivity measure is at least 100?
(1) When c=>100, b=>50.
(2) When c=100, a=100.
what I struggled with the question
I think the correct choice should have been E because,
let's take c= 1000 and b=50, then if b= 100; c=500 that is greater than 200 let's take c= 100 and b=50, then if b= 100; c=50 that is less than 200, this inconsistency make the first stament insufficient.
Also, both together are not sufficient. Merging similar topics. Please refer to the discussion above.
_________________
New to the Math Forum? Please read this: Ultimate GMAT Quantitative Megathread  All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests? Extrahard Quant Tests with Brilliant Analytics



Board of Directors
Joined: 17 Jul 2014
Posts: 2726
Location: United States (IL)
Concentration: Finance, Economics
GPA: 3.92
WE: General Management (Transportation)

Re: At RW Press, the advertising rate, a, is inversely [#permalink]
Show Tags
04 Feb 2016, 19:19
we are told that a=1/b, and b=1/c, or a=c. B and D we can eliminate right away, because we are told the same information. C=100 while A=100. Thus, it must be A, C, or E. C is highly unlikely, as there is no much new information given picked A...but confused with the terms used here... i think it should be specified that big letters are constants..



Intern
Joined: 12 Jan 2017
Posts: 43
Location: India
Concentration: Operations, Leadership

Re: At RW Press, the advertising rate, a, is inversely [#permalink]
Show Tags
08 Jun 2017, 11:11
BunuelI could understand the above explanation....can you please help ? If in the relation between c and b, if the constant is 30000,can't b=150 and c=200?



Manager
Joined: 02 Mar 2017
Posts: 93

At RW Press, the advertising rate, a, is inversely [#permalink]
Show Tags
30 Jul 2017, 06:07
Bunuel Please help. Why is everyone plugging the value of C= 100 and b=50 for option A, we can try c=100000 and b=50. From this option A can be both true or false. NO?



Senior Manager
Joined: 02 Apr 2014
Posts: 486

At RW Press, the advertising rate, a, is inversely [#permalink]
Show Tags
09 Apr 2018, 05:17
Hi Bunuel, I have a question, Let the relation between b and c be b = k/c , where k is constant Statement 1: when c >= 100, b >= 50 Let c = 100, b = 50, then k = 5000 if b >= 100, then c <= 50 ( C is lesser than 200) but as per statement 1, if we take c = 1000 (which is greater than 100) and b = 50 then k = 50000 now if b>= 100, then c <= 500 now C could be greater than 200 Can you please tell me where i am going wrong? Thanks




At RW Press, the advertising rate, a, is inversely
[#permalink]
09 Apr 2018, 05:17






