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At the 2016 convention for Aim Far Motivational Society (AFMS), each

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At the 2016 convention for Aim Far Motivational Society (AFMS), each  [#permalink]

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New post 17 Jul 2016, 11:29
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Question Stats:

62% (01:43) correct 38% (01:49) wrong based on 82 sessions

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At the 2016 convention for Aim Far Motivational Society (AFMS), each AFMS member had the option of inviting just one non-member guest. Attending as the single guest of a member is the only way a non-member would be able to attend the convention. At the 2016 convention, of the AFMS Convention Hall’s seats, 60% were occupied by AFMS members and 10% were occupied by non-member guest. How many seat does the AFMS Convention Hall have?

(1) If 60% of the members who didn’t bring a guest instead had brought one, then the hall would have been 100% full.

(2) The number of empty seats was half the number of the AFMS members present.

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At the 2016 convention for Aim Far Motivational Society (AFMS), each  [#permalink]

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New post 17 Jul 2016, 23:09
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STEM:let, total # of seats of the Hall=x
then,
# of seats occupied by members=60% of x
# of seats occupied by guest =10% of x
# of empty seats =(100-60-10)% of x=30% of x
# of the members who didn’t bring a guest =(60-10)% of x= 50% of x
x=?

STAT-1: 60% of the members who didn’t bring a guest=60% of 50% of x=30% of x
30% of x (empty #of seats) is needed to be 100% full. Already said in stem. No new information is here.....insufficient

STAT-2: half the number of the AFMS members present=1/2*60% of x=30% of x (empty #of seats)
Already said in stem. No new information is here.....insufficient

As no new information is in stat-1 and stat-2, nothing to combine.

Ans: E
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Re: At the 2016 convention for Aim Far Motivational Society (AFMS), each  [#permalink]

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New post 21 Jul 2016, 09:30
Bunuel wrote:
At the 2016 convention for Aim Far Motivational Society (AFMS), each AFMS member had the option of inviting just one non-member guest. Attending as the single guest of a member is the only way a non-member would be able to attend the convention. At the 2016 convention, of the AFMS Convention Hall’s seats, 60% were occupied by AFMS members and 10% were occupied by non-member guest. How many seat does the AFMS Convention Hall have?

(1) If 60% of the members who didn’t bring a guest instead had brought one, then the hall would have been 100% full.

(2) The number of empty seats was half the number of the AFMS members present.


Let total seat be 100x.

Seats occupied by members = 60x.

seats occupied by Guests =10x.

Left seats= 30x.

Members who dont had guests = 60x-10x=50x.

statement 1 : 60% of Non Guest Members = 30 x = seats left. But this information can be taken out of the question itself. Hence nothing new is provided here. Insufficient.

Statement 2 : Lefts seats = half the number of AFSM Members. We already know in the question that 30x= half of 60x. Hence no new information. Insufficient.

Together, no new information to find the total number of seats.

Hence ans is E.
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Re: At the 2016 convention for Aim Far Motivational Society (AFMS), each  [#permalink]

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New post 21 Jul 2016, 10:41
Bunuel wrote:
At the 2016 convention for Aim Far Motivational Society (AFMS), each AFMS member had the option of inviting just one non-member guest. Attending as the single guest of a member is the only way a non-member would be able to attend the convention. At the 2016 convention, of the AFMS Convention Hall’s seats, 60% were occupied by AFMS members and 10% were occupied by non-member guest. How many seat does the AFMS Convention Hall have?

(1) If 60% of the members who didn’t bring a guest instead had brought one, then the hall would have been 100% full.

(2) The number of empty seats was half the number of the AFMS members present.


(1) If 60% of the members who didn’t bring a guest instead had brought one, then the hall would have been 100% full.
Since we are given that 10% are filled by non-members and 60% is filled by members, we can conclude that 50% of members did not bring guests.

If 60% of 50% had brought guests, full seats would have been full. i.e 30% more people would have filled full seats. But we are not given any number to work on percentage.

Not sufficient.

(2) The number of empty seats was half the number of the AFMS members present.

Empty seats were 60%/2= 30%. But, again we are not given any numbers to work with. Not sufficient.

Combining both statements is not sufficient since no number is given.

E is the answer
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At the 2016 convention for Aim Far Motivational Society (AFMS), each A  [#permalink]

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New post 25 Jul 2016, 16:06
At the 2016 convention for Aim Far Motivational Society (AFMS), each AFMS member had the option of inviting just one non-member guest. Attending as the single guest of a member is the only way a non-member would be able to attend the convention. At the 2016 convention, of the AFMS Convention Hall’s seats, 60% were occupied by AFMS members and 10% were occupied by non-member guest. How many seats does the AFMS Convention Hall have?

Statement #1: If 60% of the members who didn’t bring a guest instead had brought one, then the hall would have been 100% full.

Statement #2: The number of empty seats was half the number of the AFMS members present.


This DS problem contains a tautological statement. There is a subtle logical different in deciding that a statement is tautological or merely insufficient. For a discussion of the implication for DS logic, as well as the OE for this problem, see:
GMAT Data Sufficiency Logic: Tautological Statements

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Re: At the 2016 convention for Aim Far Motivational Society (AFMS), each A  [#permalink]

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New post 25 Jul 2016, 20:00
mikemcgarry wrote:
At the 2016 convention for Aim Far Motivational Society (AFMS), each AFMS member had the option of inviting just one non-member guest. Attending as the single guest of a member is the only way a non-member would be able to attend the convention. At the 2016 convention, of the AFMS Convention Hall’s seats, 60% were occupied by AFMS members and 10% were occupied by non-member guest. How many seats does the AFMS Convention Hall have?

Statement #1: If 60% of the members who didn’t bring a guest instead had brought one, then the hall would have been 100% full.

Statement #2: The number of empty seats was half the number of the AFMS members present.


This DS problem contains a tautological statement. There is a subtle logical different in deciding that a statement is tautological or merely insufficient. For a discussion of the implication for DS logic, as well as the OE for this problem, see:
GMAT Data Sufficiency Logic: Tautological Statements

Mike :-)


Prompt:

number of seats = x
AFMS = .6x
AFMS without guest = .5x
AFMS with guests = .1x
Guests = .1x
Entry seats = .3x


Statement 1:

Empty seats = 60% of AFMS without guests
Empty seats = .6 * .5x = .3x= -> already known (mathematical tautology)

Statement 2:

Empty seats = half of AFMS seats
.3x = .5 * .6x (mathematical tautology)





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Re: At the 2016 convention for Aim Far Motivational Society (AFMS), each  [#permalink]

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