At the beginning of 2007, a company had x employees. To handle

1. Let's model the question. The company starts off with x employees.

2. Then in 2007 it added p% employees. So, there was a total number of \(x + x * p\%\).

3. In 2008 they layed off q%. So, the total number of employees was \((x + x * p\%) - (x + x * p\%) * q\%\).

4. It is known that the final value is x. That means we have the following equation: \(x = (x + x * p\%) - (x + x * p\%) * q\%\).

5. Let's simplify \(x = (x + x * p\%) - (x + x * p\%) * q\% \rightarrow 0 = x * p\% - x * q\% - x * p\% * q\% = x(p\% - q\% - p\% * q\%)\).

6. x is not zero, so \(0 = p\% - q\% - p\% * q\% \rightarrow p\%(1 - q\%) = q\% \rightarrow p\% = \frac{q\%}{1 - q\%}\).

7. Let's plug in the values for q and see what p we get:

- q = 10. \(\frac{10\%}{1 - 10\%} = \frac{0.1}{1 - 0.1} \approx 0.111 = 11.1\%\), 11.1 isn't an answer choice for p.
- q = 15. \(\frac{15\%}{1 - 15\%} = \frac{0.15}{1 - 0.15} \approx 0.176 = 17.6\%\), 17.6 isn't an answer choice for p.
- q = 20. \(\frac{20\%}{1 - 20\%} = \frac{0.2}{1 - 0.2} = 0.25 = 25\%\), 25 is an answer choice for p.
- q = 25. \(\frac{25\%}{1 - 25\%} = \frac{0.25}{1 - 0.25} \approx 0.333 = 33.3\%\), 33.3 isn't an answer choice for p.
- q = 50. \(\frac{50\%}{1 - 50\%} = \frac{0.5}{1 - 0.5} = 1 = 100\%\), 100 isn't an answer choice for p.
- q = 75. \(\frac{75\%}{1 - 75\%} = \frac{0.75}{1 - 0.75} = 3 = 300\%\), 300 isn't an answer choice for p.

8. Our answer will be: p - 25 and q - 20.