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08 Oct 2013, 05:50
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C
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Difficulty:
35%
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Question Stats:
74% (01:46) correct
26%
(01:47)
wrong
based on 185
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At the Butterfly Scout Cookie Chow Down, each girl was given equal time to decorate as many cookies as possible. If the winner took an average of 20 seconds to decorate each cookie, how many cookies did the second-place finisher decorate?
(1) The second-place finisher was only able to decorate at half the rate of the winner.
(2) The winner decorated 15 more cookies than the second-place finisher.
(1) The second-place finisher was only able to decorate at half the rate of the winner.
(2) The winner decorated 15 more cookies than the second-place finisher.
08 Oct 2013, 06:24
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At the Butterfly Scout Cookie Chow Down, each girl was given equal time to decorate as many cookies as possible. If the winner took an average of 20 seconds to decorate each cookie, how many cookies did the second-place finisher decorate?
(1) The second-place finisher was only able to decorate at half the rate of the winner --> first = x cookies, and second = x/2 cookies. Not sufficient.
(2) The winner decorated 15 more cookies than the second-place finisher. first = x cookies, and second = x-15 cookies. Not sufficient.
(1)+(2) x/2 = x - 15. We can solve for x. Sufficient.
Answer: C.
(1) The second-place finisher was only able to decorate at half the rate of the winner --> first = x cookies, and second = x/2 cookies. Not sufficient.
(2) The winner decorated 15 more cookies than the second-place finisher. first = x cookies, and second = x-15 cookies. Not sufficient.
(1)+(2) x/2 = x - 15. We can solve for x. Sufficient.
Answer: C.
unceldolan
Joined: 21 Oct 2013
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Schools: Owen '17 (A$) Sauder '17 (A$) Schulich '17 (WD) Anderson FEMBA '17 (S) McDonough '17 (A) Desautels '17 (S)
GMAT 1: 660 Q45 V36
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Schools: Owen '17 (A$) Sauder '17 (A$) Schulich '17 (WD) Anderson FEMBA '17 (S) McDonough '17 (A) Desautels '17 (S)
GMAT 1: 660 Q45 V36
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30 Jan 2014, 07:12
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Answer is C.
From question: Cookies (c) winner: c = Rate (r) * t ==> 1c = 1/20 c/s * t. (She takes 20 seconds per cookie).
(1) Rate of second place: 1/40. c = 1/40 * t. No Info about time or cookies. IS.
(2) c(2nd Place)+15 = 1/20 * t. No info about time or cookies. IS.
Together: From (2) : c+15 = 1/20c/s * t = (c+15)*20 = t. From (1) c = 1/40 * t. Now we can plug in t from (2) in (1) and calculate. Suff. Thus C.
Hope it helps!
From question: Cookies (c) winner: c = Rate (r) * t ==> 1c = 1/20 c/s * t. (She takes 20 seconds per cookie).
(1) Rate of second place: 1/40. c = 1/40 * t. No Info about time or cookies. IS.
(2) c(2nd Place)+15 = 1/20 * t. No info about time or cookies. IS.
Together: From (2) : c+15 = 1/20c/s * t = (c+15)*20 = t. From (1) c = 1/40 * t. Now we can plug in t from (2) in (1) and calculate. Suff. Thus C.
Hope it helps!
