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28 Apr 2025, 04:26
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Audrey's rate of work = \(A\) = \(\frac{1}{4}\)
Ferris's rate of work = \(F\) = \(\frac{1}{3}\)
Audrey works for the entirety of the \(2\) hours and Ferris take \(3\) breaks of equal length.
Let the total time of Ferris's \(3\) breaks be \(x\) hours. Then Ferris only worked for \((2-x)\) hours.
Now set up the \(Rate*Time=Work\) equation. Let the work be \(1\) unit of work.
\(2A + (2-x)F = 1\)
\(2A + 2F - xF = 1\)
\(2(\frac{1}{4}) + 2(\frac{1}{3}) - x(\frac{1}{3}) = 1\)
\(\frac{1}{2} + \frac{2}{3} - \frac{x}{3} = 1\)
\(\frac{3+4-2x}{6} = 1\)
\(-2x = 6-7\)
\(x = \frac{1}{2}\)
His total \(3\) part break was \(\frac{1}{2}\) hours long. So each part will be \(\frac{1}{2*3}\) hours long.
Converting \(\frac{1}{6}\) hours to minutes -> \(\frac{1}{6}*60\) = \(10\) minutes
Ferris's rate of work = \(F\) = \(\frac{1}{3}\)
Audrey works for the entirety of the \(2\) hours and Ferris take \(3\) breaks of equal length.
Let the total time of Ferris's \(3\) breaks be \(x\) hours. Then Ferris only worked for \((2-x)\) hours.
Now set up the \(Rate*Time=Work\) equation. Let the work be \(1\) unit of work.
\(2A + (2-x)F = 1\)
\(2A + 2F - xF = 1\)
\(2(\frac{1}{4}) + 2(\frac{1}{3}) - x(\frac{1}{3}) = 1\)
\(\frac{1}{2} + \frac{2}{3} - \frac{x}{3} = 1\)
\(\frac{3+4-2x}{6} = 1\)
\(-2x = 6-7\)
\(x = \frac{1}{2}\)
His total \(3\) part break was \(\frac{1}{2}\) hours long. So each part will be \(\frac{1}{2*3}\) hours long.
Converting \(\frac{1}{6}\) hours to minutes -> \(\frac{1}{6}*60\) = \(10\) minutes
ravi1522
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Hello ,
As A takes 4 hours and F take 3 hours to complete work
As work is completed in 2 hours ,Then A would have completed 50% works in 2 hours.
Remaining 50% F will do. As per original rate it should take F to do 50% in 1.5 hours ,but he took 2 hours
so that additional 30 minutes will be break which was taken 3 times .So each breaks will be 30/3=10 minutes .
Hence option B is correct
I hope it helps
As A takes 4 hours and F take 3 hours to complete work
As work is completed in 2 hours ,Then A would have completed 50% works in 2 hours.
Remaining 50% F will do. As per original rate it should take F to do 50% in 1.5 hours ,but he took 2 hours
so that additional 30 minutes will be break which was taken 3 times .So each breaks will be 30/3=10 minutes .
Hence option B is correct
I hope it helps
27 Aug 2025, 07:45
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logically,
so A does 1/2 of the work because she is working for complete 2 hrs at her 1/4 rate.
so work left is 1/2 and the other fella works at 1/3 rate for X hrs to complete that
so he takes, 1/2 = x/3 --> x = 3/2 hrs, (i.e 1.5) and so 2-1.5 = 0.5 * 60 = 30 mins / 3 = 10 mins equal breaks
so A does 1/2 of the work because she is working for complete 2 hrs at her 1/4 rate.
so work left is 1/2 and the other fella works at 1/3 rate for X hrs to complete that
so he takes, 1/2 = x/3 --> x = 3/2 hrs, (i.e 1.5) and so 2-1.5 = 0.5 * 60 = 30 mins / 3 = 10 mins equal breaks
