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Barry walks from one end to the other of a 30-meter long [#permalink]

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20 Oct 2012, 09:12

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Barry walks from one end to the other of a 30-meter long moving walkway at a constant rate in 30 seconds, assisted by the walkway. When he reaches the end, he reverses direction and continues walking with the same speed, but this time it takes him 120 seconds because he is traveling against the direction of the moving walkway. If the walkway were to stop moving, how many seconds would it take Barry to walk from one end of the walkway to the other?

Re: Barry walks from one end to the other of a 30-meter long [#permalink]

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20 Oct 2012, 11:55

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nitzz wrote:

Barry walks from one end to the other of a 30-meter long moving walkway at a constant rate in 30 seconds, assisted by the walkway. When he reaches the end, he reverses direction and continues walking with the same speed, but this time it takes him 120 seconds because he is traveling against the direction of the moving walkway. If the walkway were to stop moving, how many seconds would it take Barry to walk from one end of the walkway to the other?

A) 48 B) 60 C) 72 D) 75 E) 80

Let Barry's speed be x m/s and walkway's speed by y m/s. We need to find 30/x.

If Barry walks in the direction of the moving walkway, the total speed is x + y. Time taken is 30/(x+y) Thus, 30/(x+y) = 30

=> x + y = 1 ... (1)

If Barry walks against the moving walkway's direction, total speed is x-y. Time take is 30(x-y) Thus, 30/(x-y) = 120

Barry walks from one end to the other of a 30-meter long moving walkway at a constant rate in 30 seconds, assisted by the walkway. When he reaches the end, he reverses direction and continues walking with the same speed, but this time it takes him 120 seconds because he is traveling against the direction of the moving walkway. If the walkway were to stop moving, how many seconds would it take Barry to walk from one end of the walkway to the other?

A) 48 B) 60 C) 72 D) 75 E) 80

Say Barry's speed is \(b\) meter per second and walkaway speed is \(w\) meter per second, then as \(Speed=\frac{Distance}{Time}\) we'll have that:

Re: Barry walks from one end to the other of a 30-meter long [#permalink]

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31 Dec 2013, 09:03

nitzz wrote:

Barry walks from one end to the other of a 30-meter long moving walkway at a constant rate in 30 seconds, assisted by the walkway. When he reaches the end, he reverses direction and continues walking with the same speed, but this time it takes him 120 seconds because he is traveling against the direction of the moving walkway. If the walkway were to stop moving, how many seconds would it take Barry to walk from one end of the walkway to the other?

Re: Barry walks from one end to the other of a 30-meter long [#permalink]

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20 May 2014, 05:48

Do we actually need to know that the distance is 30 meters?

IF we learn that w=3b/5 we can find distance in terms of 'b' and then divide by rate 'b' to figure out that it will take Ben 48 seconds to reach the end of the walkway

Re: Barry walks from one end to the other of a 30-meter long [#permalink]

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20 May 2014, 06:03

jlgdr wrote:

Do we actually need to know that the distance is 30 meters?

IF we learn that w=3b/5 we can find distance in terms of 'b' and then divide by rate 'b' to figure out that it will take Ben 48 seconds to reach the end of the walkway

Please advice Cheers! J

No we don't need this value of 30 meters since the distance remains the same while travelling up and down and thus, speeds are inversely proportional to the time taken. The information is superfluous.

Re: Barry walks from one end to the other of a 30-meter long [#permalink]

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17 Jun 2015, 15:43

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Re: Barry walks from one end to the other of a 30-meter long [#permalink]

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26 Jun 2016, 08:30

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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Barry walks from one end to the other of a 30-meter long [#permalink]

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26 Jun 2016, 23:36

s1 = 30/30 = 1 metre/sec s2 = 30/120 = 0.25 metres/sec now x+y=1 x-y=0.25 or, 2x=1.25 ==> x = 0.625 metres/sec and y = 0.375 metres/sec time taken by barry = 30000/625=48 sec

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