Total no of ways selecting 4 cards = 12x11x10x9
Total no of ways selecting all 4 different cards =12(any card) x 10(all card except the one already selected and the one with same number)x8(all card except the two already selected and the two with same numbers)x6(all card except the three already selected and the three with same number )
Probability of selecting all diff cards = 12x10x8x6/12x11x10x9 =16/33
probability of selecting at least 1 pair = 1-16/33 = 17/33
maheshsrini
Bill has a small deck of 12 playing cards made up of only 2 suits of 6 cards each. Each of the 6 cards within a suit has a different value from 1 to 6; thus, for each value from 1 to 6, there are two cards in the deck with that value. Bill likes to play a game in which he shuffles the deck, turns over 4 cards, and looks for pairs of cards that have the same value. What is the chance that Bill finds at least one pair of cards that have the same value?
A. 8/33
A. 62/165
C. 17/33
D. 103/165
E. 25/33