Bill travels first 40% of the distance to his destination at

Question

Bill travels first 40% of the distance to his destination at 80 mph and covered the balance distance at 40 mph. What is the average speed of his travel?

A) 45
B) 38
C) 50
D) 52
E) 55

Source: 4gmat

Bunuel · Accepted Answer

Say total distance is 100 miles (first part 40 miles and second part 60 miles), then  average \ speed=\frac{total \ distance}{total \ time}=\frac{100}{\frac{40}{80}+\frac{60}{40}}=50 .

Answer; C.

EvaJager · Answer

Average speed can be computed as (total distance)/(total time).
In our case, if we denote by D the distance, then the average speed is given by:

S_a=\frac{D}{\frac{0.4D}{80}+\frac{0.6D}{40}}=...=50 
The distance cancels out in the above computations.

Answer C

SOURH7WK · Answer

Can we put it into any kind of formula to solve this kind of problem Quickly???

Bunuel · Answer

Well, formula can be derived, though I don't think that memorizing such kind of formulas is more time efficient than understating the logic behind it.

If the total distance is  d=m+n  kilometers, and  m  kilometers is covered at  r_1  kilometers per hour while  n  kilometers is covered at  r_2  kilometers per hour, then  average \ speed=\frac{total \ distance}{total \ time}=\frac{m+n}{\frac{m}{r_1}+\frac{n}{r_2}} .

Apex231 · Answer

Why doesn't weighted average formula work in this case?

(80 * 0.4) + (40 * 0.6) = 32 + 24 = 56

or

let average speed be s.

(80-s)/(s-40) = 3/2
s = 56

KarishmaB · Answer

Because in the weighted average formula, when you are trying to find the average speed, the weights will be the time taken, not the distance traveled. Here 0.4 and 0.6 is the distance traveled. You have to be careful when you are choosing the weights. Check out a related discussion here: a-certain-car-traveled-twice-as-many-miles-from-town-a-108368.html#p859543

Apex231 · Answer

I am still not sure of how to correctly identify whether time or distance be considered as value/weight in weighted avg formula. Is there a generic rule to identify this?

chiccufrazer1 · Answer

@Bunuel,is it true that we always solve average speed problems by plugin method? :O

Posted from my mobile device

Bunuel · Answer

No, definitely not ALWAYS. But when fractions and/or percentages are involved to define distance for example, then we can assign some number to it and proceed this way.

Apex231 · Answer

Can someone explain why time and not distance is considered in weighted avg formula for speed?; just trying to understand concepts.

KarishmaB · Answer

Speed is measured in miles/hr.
The weights will be in 'hr'

Look at the weighted average formula:

Cavg = (C1*w1 + C2*w2)/(w1 + w2) = miles/hr = (miles/hr * hr + miles/hr * hr) / (hr + hr) = (miles + miles)/(hr + hr) i.e. total distance/total time

weights cannot be distance: miles/hr = (miles/hr * miles + miles/hr * miles) / (miles + miles) -> miles^2/hr is no physical quantity.

Did you check out the link I gave you above? It discusses this concept with miles/gallon. Weights should be in gallons here.

minwoswoh · Answer

Bill travels first 40% of the distance to his destination at 80 mph and covered the balance distance at 40 mph. What is the average speed of his travel?

When we have these Average Rate for the whole trip problems, the key is to understand that:
- We only need the Rates of both part of the trips.
- We can plug in for Distance and infer for Time
- Then, you just have to solve the simple formula (Distance 1 + Distance 2) / (Time 1 + Time 2)

I´ll tell you how I did this in around 75 seconds with the RTD chart

Question Stem
 R * T = D 
1st Part: 80 * ? =(0.4) d
2nd Part: 40 * ? =(0.6) d

Note that Rates, Times, and Distances ARE ALL DIFFERENT in each part of the trip.

Next, come up with some Distances to plug in (400 and 600 are a safe bet here)
 R * T = D 
1st Part: 80 * ? = 400
2nd Part: 40 * ? =600

Now, deduce the Times for each part of the trip
 R * T = D 
1st Part: 80 * 5 = 400
2nd Part: 40 * 15 =600

Now, solve the Average Rate Formula
(400 + 600) / (5 + 15) = 1,000/20 = 50

I know it looks time consuming but this is just because I broke every step down. You obviously don´t need to do 3 charts: it is just the same chart in each step of the resolution.

Hope it helps!

gurmukh · Answer

Average speed =
total distance / total time 
Let distance =100
 Therefore
100/(40/80 + 60/40)

=100/(0.5+1.5)
 = 50
Option C is the answer

Posted from my mobile device

bumpbot · Answer

Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.

Bill travels first 40% of the distance to his destination at

Prep Toolkit

Top 5 GMAT Debrief Videos

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards

GMAT Problem Solving (PS) Questions

Bill travels first 40% of the distance to his destination at

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards