AjiteshArun
hadimadi
AjiteshArun,
KarishmaBHi
AjiteshArun,
let x be the number of potential donors, and N be the number of people who actually have NANB.
We know that 2/3N won't be detected, and that 1/3N is contained in the 0.05x:
1/3N <= 0.05x
I put smaller and equal because:
We know the test is not 100% accurate, since 2/3N are not being detected. So when 5% of people are disqualified, it could be that at least some are falsely tested positive. So on top of the 1/3N who actually have the disease, we have some potential unknown amount of people who are false positives.
Now we can follow:
2/3N <= 0.1x
And now, even (A) won't work as an answer choice.
Where did I go wrong?
Hi
hadimadi,
You seem to be mostly on the right track (just remember that we don't want to take \(x\) in both cases, because the second total does not involve all of \(x\), and the second total is not exactly 10% of something else), but false positives don't play an important role in the author's argument
(in fact, he or she doesn't even mention false positives).That said, it'd help if you could tell us why you think option A won't work. Until then, let's include the possibility of false positives, and then try to work with actual numbers.
\(\frac{1}{3}N_{prospective\:donors\:with\:NANB}+N_{prospective\:donors,\:false\:positives}\leq\frac{5}{100}N_{prospective\:donors}\)
If we start with 100 prospective donors, the test is estimated to reject up to 5. It's worth noting that 5 is the maximum number of prospective donors with NANB that the test is estimated to reject. This is the number the author seems to be using, so we'll also use it. Now, there are two important points to keep in mind here:
1. We've been looking at
prospective donors till now. If this is the only test, the number of
actual donors is 95, not 100.
2. This is an assumption question. The process of solving this question will involve
understanding how the author reached his or her conclusion.
Point (2) is particularly important. Whatever else we do to solve the question,
the answer we choose must, at the end of the day, help us get to the author's conclusion.
So, how
did the author reach the conclusion that "about 10 percent of actual donors will still supply NANB-contaminated blood"? Clearly, it's not by maximising the number of false positives. For example, if we assume that 4 out of the 5 rejected prospective donors were false positives, that would leave us with \(\frac{1}{3}N_{prospective\:donors\:with\:NANB}=1\), which would mean that the number of prospective donors with NANB is 3 and the number of actual donors with NANB is just 2, which is not particularly close to "about 10 percent" of 95.
What the author has done here is assume that the number of false positives is very low. As far as the author is concerned, the number of false positives is 0 if we assume the total number of prospective donors to be 100. That means the test takes
~5 prospective donors with NANB out, leaving 10 actual donors with NANB. \(\frac{10}{95}\) is
~0.105, and we can now see how the author got to "about 10% of actual donors".
Finally, why is A correct? One weakness in the argument is that it does not take into account the possibility that there could be other (
reliable) screening processes for other problems. If people with NANB-contaminated blood
do have other problems that other reliable screening methods can detect, then the conclusion that about 10% of donors will donate NANB-contaminated blood is weakened, as these people will get "screened out" by these other tests.
Hi
AjiteshArun,
the yellow part:Just because something is not mentioned in the argument explicitly it doesn't mean that one should still be aware of all cases - in many CR questions in fact the solution is hidden in some apparently small words (i.e., when there are 100 vehicles caught by a speed camera, it doesn't mean that we have 100 different drivers. Same way, if we have 5% disqualified, I can't just go and assume that all really have the diseases unless otherwise is being told in the question stem)
the red part:This is an assumption you are making, and not the author himself anywhere in his argument, so we can't just take it as 'it is implicitly assumed', because exactly this could be faulty in his argument / the missing link which the answer choice could be looking for.
However, to assume that false positives are non existent is necessary for this argument. But it is nowhere mentioned. Not even in an answer choice. Now, one could argue that there might be several necessary conditions for an assumption question to hold true, so it doesn't need to be mentioned anywhere.
Alright, then let's not make any assumptions about the
number of false positives, and just look at the question stem and answer choices (now we don't assume anything about how many false positives there are in the 5%):
Not (A)
and other premises from question stem -> Not Conclusion
X=A large percentage of those who carry NANB carry other diseases that are reliably and routinely tested for (this is our not (A))
Y= 5% of potential donors are disqualified (
potentially including false positives)
Z= Exactly 2/3 of people that carry the disease are in the 95% that become actual donors
N=Total number of people actually carrying NANB
E=Total potential donors
X
and Y
and Z -> The percentage of actual donors carrying NANB is not around 10%
From Y: N/3<=0.05E -> 2N/3<= 0.1E
From Z: (2N/3)/(0.95E), this is the share of people carrying NANB in the a total of 0.95E
Combining these findings, we get: (2N/3)/(0.95E) <= (0.1E)/(0.95E) = 0.1/0.95 = approx. 0.1
In total: The share of people carrying NANB of the 0.95E, where 0.95E=actual donors, is
smaller than or equal to 10%. Let's name this finding F. Hence:
F
and X -> The percentage of actual donors carrying NANB is not around 10%
Since X tells us that there are very likely fewer people carrying the disease, meaning N is smaller than what we assumed it to be. Now since F is equal to:
(2N/3)/(0.95E)<=0.1x, and we know that we will have fewer than 2N/3 people who will actually become donors, we get:
(Some number smaller than (2N/3)/(0.95E))< (2N/3)/(0.95E) <= 0.1x
-> ((Some number smaller than (2N/3)/(0.95E)) < 0.1x
But this is exactly our not (A).
This now looks fine to me, at least I hope it is correct

Thanks for your tremendous help!!