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srichaks
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T = 2000 (total value of bonds)
we know that the only denominations he bought the bonds are 50 and 100 so we can write this as an algerbraic equation

50a + 100b = 2000

--> a + 2b = 40 --(a)

now lets look at choices and see which one fits

A) a + b = 20
so a = 20 -b

putting this into equation

20 - b + 2b = 40
b = 20 ...so it is possible


B) 27 - b + 2b = 40
b = 13

Moving on to D

D) 40 + b = 40
b = 0
so possible because a = 40 in this case

E) 50 + b = 40
b = -10
ok this is not possible and that shows that this is our answer
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this question need a logic rather than math skills, the maximum no. of bond which is be purchased is 40 ( 2000/50) hence any no. greater than 40 is not posssible hence ans E



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