Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
23 Nov 2014, 13:35
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
69% (00:59) correct
31%
(00:54)
wrong
based on 588
sessions
History
Date
Time
Result
Not Attempted Yet
Brian takes a weekend trip to visit a friend. What is his average rate for the there-and-back trip?
(1) Brian took the same route for both segments.
(2) Brian averaged 80 mph for the first segment and 50 mph for the second segment.
(1) Brian took the same route for both segments.
(2) Brian averaged 80 mph for the first segment and 50 mph for the second segment.
24 Nov 2014, 02:57
Kudos
Bookmarks
aashu4uiit
st.1 : clearly not sufficient. as nothing is mentioned about the rates.
st.2 : tells us about the rate. but nothing is mentioned about the segments. i.e. whether brian took the same route for both segments or he took the different route for each segment.
st.1 and st.2
we know that brain follows the same route for each segment. hence Distance traveled in each segment is constant. therefore, average speed can be calculated as
avg. speed = \(\frac{total distance}{total time}\\
\\
= \frac{2D}{D/80 +D/50}\\
=\frac{2.80.50}{80+50}\\
=\frac{800}{13}\\
=61.5\)
hence answer should be C
General Discussion
24 Nov 2014, 04:53
Kudos
Bookmarks
since , Average rate = total distance/total time
1) Brian took the same route for both segments.
This statement only talk about distances and no information as to how much Brian has covered been given.
INSUFFICIENT.
2) Brian averaged 80 mph for the first segment and 50 mph for the second segment.
This statement provides the respective average speed taken during the each way of the journey.
But again there is no information as to how much distances were covered during each trip.
INSUFFICIENT.
If we combine both the statements Average rate = 2x/(x/80 +x/50). SUFFICIENT.
Answer C
1) Brian took the same route for both segments.
This statement only talk about distances and no information as to how much Brian has covered been given.
INSUFFICIENT.
2) Brian averaged 80 mph for the first segment and 50 mph for the second segment.
This statement provides the respective average speed taken during the each way of the journey.
But again there is no information as to how much distances were covered during each trip.
INSUFFICIENT.
If we combine both the statements Average rate = 2x/(x/80 +x/50). SUFFICIENT.
Answer C
