To find the probability that one piece of fruit selected will be an apple and the other will be an orange, we need to consider the possible combinations of selecting one fruit from each basket.
In the first basket, there are 4 apples and 2 oranges, and in the second basket, there are 3 apples and 5 oranges.
The total number of possible outcomes is the product of the number of fruits in each basket: 6 (total fruits in the first basket) * 8 (total fruits in the second basket) = 48.
Now, let's consider the favorable outcomes where one fruit is an apple and the other is an orange.
Selecting an apple from the first basket and an orange from the second basket:
The probability of selecting an apple from the first basket is 4/6, and the probability of selecting an orange from the second basket is 5/8.
Probability = (4/6) * (5/8) = 20/48.
Selecting an orange from the first basket and an apple from the second basket:
The probability of selecting an orange from the first basket is 2/6, and the probability of selecting an apple from the second basket is 3/8.
Probability = (2/6) * (3/8) = 6/48.
Adding up the probabilities of the two favorable outcomes, we get (20/48) + (6/48) = 26/48.
Simplifying this fraction, we get 13/24.