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# Cars A, B moves towards each other, the distance between

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CEO
Joined: 15 Aug 2003
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Cars A, B moves towards each other, the distance between [#permalink]

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13 Sep 2003, 05:25
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Cars A, B moves towards each other, the distance between them at
the beginning is 250 mile, they meet after 2 hours. which one is
further away from its starting point when they meet?

1) When they met, A's speed was averaged 55m/hr
2) The average speed of B in entire trip was 70 m/hr.

Kudos [?]: 924 [0], given: 781

Intern
Joined: 06 Sep 2003
Posts: 19

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13 Sep 2003, 09:09
I got D.

1. 55*2+2*X=250, we may got X=70. B is futher away form the start point.

2. y*2+70*2=250, we can got y=55. The same is above.

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Intern
Joined: 13 Sep 2003
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04 Nov 2003, 12:51
I dont quite agree .
I think it should be B,because the average speed in the fiest statement is only given for the time when they meet.It doesnt assume that A's average speed for the whole time was 55m/hr..

but guys jump in and correct me...

sudz

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Manager
Joined: 26 Aug 2003
Posts: 232

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04 Nov 2003, 14:36
sudzpwc wrote:
I dont quite agree .
I think it should be B,because the average speed in the fiest statement is only given for the time when they meet.It doesnt assume that A's average speed for the whole time was 55m/hr..

but guys jump in and correct me...

sudz

I don't know about that.... because essentially both statements are the same as far as "average" speed of both each car is specified.

So I vote for D.

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SVP
Joined: 16 Oct 2003
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04 Nov 2003, 15:10
D is my choice of best answer.

They meet after 2 hours and till they met A's speed was 55 do 55*2 = 110

Average speed = 70 so in 2 hours 140 hence D

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Senior Manager
Joined: 11 Nov 2003
Posts: 356

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27 Nov 2003, 11:13
I would think that the answer would be A.

Statement1 : SUFF as explained by others

Statement 2: NOT SUFF. Here the average speed for the ENTIRE TRIP is given. That means average speed of B was 70 until B reached the starting position of A. This does not mean that B's speed averaged 70 when they met. What if B averaged a speed of 20 during the first TWO hours and then averaged some other speed for the remaimder of the trip in such a way that the average speed for the entire trip is 70. In this case A would be farther from the point of start. So NOT SUFF

I guess it depends on how we take the words "ENTIRE TRIP". If we take it as trip from B to A's location then the answer would be A.

If we take that just as a trip from the start to the point where they met then the answer would be D.

Personally I think we should consider the first meaning. and the answer should be A.

Any thoughts?

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GMAT Instructor
Joined: 07 Jul 2003
Posts: 769

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Location: New York NY 10024
Schools: Haas, MFE; Anderson, MBA; USC, MSEE
Re: DS : Cars [#permalink]

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28 Nov 2003, 23:56
praetorian123 wrote:
Cars A, B moves towards each other, the distance between them at
the beginning is 250 mile, they meet after 2 hours. which one is
further away from its starting point when they meet?

1) When they met, A's speed was averaged 55m/hr
2) The average speed of B in entire trip was 70 m/hr.

Remember, when you are given average speeds between two points, this only represents the "constant speed needed to travel a particular distance in a particular time". What actually happens between those two points is anyone's guess. It would be relatively easy to set up various scenarios where A and B meet all along the route given only the constrainst of (2) and the stimulus. Hence IMO A is the answer.
_________________

Best,

AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

Kudos [?]: 240 [0], given: 0

Re: DS : Cars   [#permalink] 28 Nov 2003, 23:56
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# Cars A, B moves towards each other, the distance between

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