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Circle O is inscribed in equilateral triangle ABC. If the area of ABC

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Circle O is inscribed in equilateral triangle ABC. If the area of ABC  [#permalink]

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New post 15 Nov 2019, 01:28
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A
B
C
D
E

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  35% (medium)

Question Stats:

67% (02:21) correct 33% (02:37) wrong based on 24 sessions

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Re: Circle O is inscribed in equilateral triangle ABC. If the area of ABC  [#permalink]

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New post 15 Nov 2019, 01:41
side of ∆ = 24√3 = √3*s^2/4
s= 4√6
radius of inscribed circle = s*√3/6
r= 4√6*√3/6
r= 2√18/3
area of circle = pi * ( 2√18/3)^2 = \(8\pi\)
IMO D


Bunuel wrote:
Circle O is inscribed in equilateral triangle ABC. If the area of ABC is \(24 \sqrt{3}\), what is area of circle O?


A. \(2\pi\sqrt{3}\)

B. \(4\pi\)

C. \(4\pi\sqrt{3}\)

D. \(8\pi\)

E. \(12\pi\)


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Re: Circle O is inscribed in equilateral triangle ABC. If the area of ABC  [#permalink]

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New post 17 Nov 2019, 21:51
1
Bunuel wrote:
Circle O is inscribed in equilateral triangle ABC. If the area of ABC is \(24 \sqrt{3}\), what is area of circle O?


A. \(2\pi\sqrt{3}\)

B. \(4\pi\)

C. \(4\pi\sqrt{3}\)

D. \(8\pi\)

E. \(12\pi\)


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Area of Equilateral Triangle: (√3/4)*a^2
therefore, (√3/4)*a^2= 24√3; a=4√6

The radius of a circle when inscribed in Equilateral Triangle: r = (√3a )/ 6
r= (√3*4*√6)/6
r= 2√2

Area of circle= pi*r^2
therefore, the area of a circle: pi* (2√2)^2 = 8pi

please provide the kudus :thumbup: :thumbup:
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Re: Circle O is inscribed in equilateral triangle ABC. If the area of ABC   [#permalink] 17 Nov 2019, 21:51
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Circle O is inscribed in equilateral triangle ABC. If the area of ABC

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