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Bunuel
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BN1989
Is there a way for people who don't have a facebook account to access the video?

Hi BN1989,

Yes, we've posted an HD version of the video here:

https://www.gmatpill.com/gmat-practice-t ... ons-lesson

You can post your questions here as well.

Enjoy!
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GMAT Pill video is now available in the first post: combinations-poker-probability-by-gmat-pill-142490.html#p1144000
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Best questions & answers from comments



Dimiter Kraev
Is it fair to assume that most probability questions show up when 700+?
The GMAT Pill Study Method
@Dimiter - Probability/Combinatorics is most common at the 700 level, but can also appear in the 600 area. More basic probability questions will be more prevalent at the 600 level while word problems involving choosing teams of committees will be more prevalent at the 700 level..

For those at the 500 to low 600 level, you likely won't see these types of questions. However, if you are shooting for over 700 - you're more likely to see these questions - particularly in word problem format.

Ace Richards
What about geometry? at what level do these questions show up and how many can e expect?
The GMAT Pill Study Method
Most geometry questions won't involve combinatorics. However, there are a few in the Official Guide that actually involve both coordinate geometry and combinatorics. So it is possible to see a question that combines both elements.

Of course, you'll only see these if you are consistently getting other quant questions correct and the system continually gives you more and more difficult questions - adding elements of combinatorics - possibly mixing them with other subjects like geometry.

Still the basics in the frameworks of variations vs combinations vs permutations at the beginning of the video are fair game for upper 600 level questions.


For more check: https://www.facebook.com/photo.php?fbid= ... =1&theater
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Bumped for review.

From GMAT Club's 10 Years & 1,000,000 Posts Milestone Celebration: 15 GMAT and MBA lectures jointly designed with our partners
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In the Poker Problem, "Given Pocket Aces, what is P(3 of a kind)?", why do we have to first choose for a value and then pick a suit? Why can't we simply pick 2 cards out of the remaining 48(after removing the other ace)? [2C1*48C2]
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