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19 May 2010, 23:43
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Hello Guys... On to Coordinate Geometry now.
Below are few questions I was not able to solve. Need your help in these...Thanks a lot.
1) What will be the equation of straight line 3x + 4y = 6 if the origin gets shifted to (3,-4)
a) 3x+4y=5
b) 3x+4y+1=0
c) 3x+4y=13
d) 4x-3y=4
2)If P and Q are two points on the line 3x + 4y = -15 such that OP and OQ= 9 units, The area of triangle POQ is given by
a) 18* sqrt(2)
b) 3* sqrt(2)
c) 6* sqrt(2)
d) 15*sqrt(2)
3) The equations of two sides of isoceles triangle ABC are x+y=5 and 7x-3y=3 respectively. What will be the length of the intercept cut by the side BC on the y-axis.
a) 9/5
b) 8
c) 1.5
d) no unique solution
The last one ...almost similar to the first question.
4) A line is represented by the equation 4x + 5y = 6 in the coordinate system with origin (0,0). You are required to find the equation of the straight line perpendicular to this line that passes through the point (1,-2) [which is in the coordinate system where origin is at (-2,-2)].
a)5x-4y=11
b)5x-4y=13
c)5x-4y=-3
d)5x-4y=7
Thanks again for your help.
V
Below are few questions I was not able to solve. Need your help in these...Thanks a lot.
1) What will be the equation of straight line 3x + 4y = 6 if the origin gets shifted to (3,-4)
a) 3x+4y=5
b) 3x+4y+1=0
c) 3x+4y=13
d) 4x-3y=4
2)If P and Q are two points on the line 3x + 4y = -15 such that OP and OQ= 9 units, The area of triangle POQ is given by
a) 18* sqrt(2)
b) 3* sqrt(2)
c) 6* sqrt(2)
d) 15*sqrt(2)
3) The equations of two sides of isoceles triangle ABC are x+y=5 and 7x-3y=3 respectively. What will be the length of the intercept cut by the side BC on the y-axis.
a) 9/5
b) 8
c) 1.5
d) no unique solution
The last one ...almost similar to the first question.
4) A line is represented by the equation 4x + 5y = 6 in the coordinate system with origin (0,0). You are required to find the equation of the straight line perpendicular to this line that passes through the point (1,-2) [which is in the coordinate system where origin is at (-2,-2)].
a)5x-4y=11
b)5x-4y=13
c)5x-4y=-3
d)5x-4y=7
Thanks again for your help.
V
20 May 2010, 04:49
Kudos
Bookmarks
1) C
\(x = x_{new} + 3\)
\(y = y_{new} - 4\)
\(3*(x_{new} + 3) + 4*(y_{new} - 4) = 6\)
\(3x_{new} + 9 + 4y_{new} - 16 = 6\)
\(3x_{new} + 4y_{new} = 13\)
By the way, it could be useful for you: math-coordinate-geometry-87652.html
Please, post questions in separate threads.
\(x = x_{new} + 3\)
\(y = y_{new} - 4\)
\(3*(x_{new} + 3) + 4*(y_{new} - 4) = 6\)
\(3x_{new} + 9 + 4y_{new} - 16 = 6\)
\(3x_{new} + 4y_{new} = 13\)
By the way, it could be useful for you: math-coordinate-geometry-87652.html
Please, post questions in separate threads.
10 May 2012, 07:43
Kudos
Bookmarks
in 2nd question, O is not mentioned to be origin. So, isn't it wrong to assume in GMAT?
Anyways, considering O to be origin, we can use the distance from origin and the line whose equation is given by using ax+by+c/sqrt(a2 + b2)
here (x,y) = (0,0) and equation of line is 3x+4y=-15
answer comes out to be A 18sqrt(2)
Anyways, considering O to be origin, we can use the distance from origin and the line whose equation is given by using ax+by+c/sqrt(a2 + b2)
here (x,y) = (0,0) and equation of line is 3x+4y=-15
answer comes out to be A 18sqrt(2)
