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Data Sufficiency Pack 4, Question 2) Z is a positive integer...

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Data Sufficiency Pack 4, Question 2) Z is a positive integer...  [#permalink]

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New post 20 Nov 2015, 14:21
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QUANT 4-PACK SERIES Data Sufficiency Pack 4 Question 2 Z is a positive integer...

Z is a positive integer greater than 3. How many distinct prime factors does (Z + 1)(Z – 1) have?

1) Z is not even
2) Z is not a multiple of 5


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Re: Data Sufficiency Pack 4, Question 2) Z is a positive integer...  [#permalink]

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New post 20 Nov 2015, 14:43
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EMPOWERgmatRichC wrote:
Z is a positive integer greater than 3. How many distinct prime factors does (Z + 1)(Z – 1) have?

1) Z is not even
2) Z is not a multiple of 5


Target question: How many distinct prime factors does (Z + 1)(Z – 1) have?

Given: Z is a positive integer greater than 3

Statement 1: Z is not even
This statement doesn't FEEL sufficient, so I'll TEST some values.
There are several values of Z that satisfy statement 1. Here are two:
Case a: Z = 9, in which case (Z + 1)(Z - 1) = (10)(8) = 80 = (2)(2)(2)(2)(5). In this case, we have TWO distinct prime factors
Case b: Z = 11, in which case (Z + 1)(Z - 1) = (12)(10) = 120 = (2)(2)(2)(3)(5). In this case, we have THREE distinct prime factors
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Aside: For more on this idea of plugging in values when a statement doesn't feel sufficient, you can read my article: http://www.gmatprepnow.com/articles/dat ... lug-values

Statement 2: Z is not a multiple of 5
This statement doesn't FEEL sufficient either, so I'll TEST some values.
There are several values of Z that satisfy statement 2. Here are two:
Case a: Z = 9, in which case (Z + 1)(Z - 1) = (10)(8) = 80 = (2)(2)(2)(2)(5). In this case, we have TWO distinct prime factors
Case b: Z = 11, in which case (Z + 1)(Z - 1) = (12)(10) = 120 = (2)(2)(2)(3)(5). In this case, we have THREE distinct prime factors
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Notice that I used the same values of Z for the first 2 statements. This means that the same Z-values satisfy BOTH statements.
That is:
Case a: Z = 9, in which case (Z + 1)(Z - 1) = (10)(8) = 80 = (2)(2)(2)(2)(5). In this case, we have TWO distinct prime factors
Case b: Z = 11, in which case (Z + 1)(Z - 1) = (12)(10) = 120 = (2)(2)(2)(3)(5). In this case, we have THREE distinct prime factors
Since we cannot answer the target question with certainty, the combined statements are NOT SUFFICIENT

Answer = E

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Brent
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Re: Data Sufficiency Pack 4, Question 2) Z is a positive integer...  [#permalink]

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New post 22 Nov 2015, 00:42
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

Z is a positive integer greater than 3. How many distinct prime factors does (Z + 1)(Z – 1) have?

1) Z is not even
2) Z is not a multiple of 5

There is one variable (z) and 2 equations are given by the 2 conditions, increasing the chance (D) will be our answer.
For condition 1, z=3, (3+1)(3-1)=8=2^3, the no. of distinct prime factors:1
z=7, (7+1)(7-1)=(2^4)3, the no. of distinct prime factors: 2
For condition 2, z=3, (3+1)(3-1)=8=2^3, the no. of distinct prime factors:1
z=7, (7+1)(7-1)=(2^4)3, the no. of distinct prime factors: 2
Looking at the conditions together,
z=3, (3+1)(3-1)=8=2^3, the no. of distinct prime factors:1
z=7, (7+1)(7-1)=(2^4)3, the no. of distinct prime factors: 2.
Therefore, the answer becomes (E).

For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
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Re: Data Sufficiency Pack 4, Question 2) Z is a positive integer...  [#permalink]

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New post 24 Nov 2015, 22:28
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EMPOWERgmatRichC wrote:
QUANT 4-PACK SERIES Data Sufficiency Pack 4 Question 2 Z is a positive integer...

Z is a positive integer greater than 3. How many distinct prime factors does (Z + 1)(Z – 1) have?

1) Z is not even
2) Z is not a multiple of 5


Hi All,

This question can be solved by TESTing VALUES. We're told that Z is a POSITIVE INTEGER greater than 3. We're asked for the number of DISTINCT (meaning 'different') prime factors in (Z + 1)(Z – 1).

To start, we can rewrite (Z + 1)(Z – 1) as \(Z^{2}\) - 1

1) Z is NOT even

We already know that Z is an INTEGER greater than 3...

IF...
Z = 7, then 49-1 = 48 = (2)(2)(2)(2)(3) and has 2 distinct prime factors.

IF...
Z = 11, then 121-1 = 120 = (2)(2)(2)(3)(5) and has 3 distinct prime factors.
Fact 1 is INSUFFICIENT

2) Z is not a multiple of 5

The same 2 TESTs that we used in Fact 1 will 'fit' Fact 2 as well...

IF...
Z = 7, then 49-1 = 48 = (2)(2)(2)(2)(3) and has 2 distinct prime factors.

IF...
Z = 11, then 121-1 = 120 = (2)(2)(2)(3)(5) and has 3 distinct prime factors.
Fact 2 is INSUFFICIENT

Combined, we can see that the same two TESTs 'fit' both Facts, but yield two different answers.
Combined, INSUFFICIENT

Final Answer:

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Re: Data Sufficiency Pack 4, Question 2) Z is a positive integer...  [#permalink]

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New post 07 Jun 2017, 02:49
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As given in question statement Z>3. So we can not take Z=3.

Regards


MathRevolution wrote:
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

Z is a positive integer greater than 3. How many distinct prime factors does (Z + 1)(Z – 1) have?

1) Z is not even
2) Z is not a multiple of 5

There is one variable (z) and 2 equations are given by the 2 conditions, increasing the chance (D) will be our answer.
For condition 1, z=3, (3+1)(3-1)=8=2^3, the no. of distinct prime factors:1
z=7, (7+1)(7-1)=(2^4)3, the no. of distinct prime factors: 2
For condition 2, z=3, (3+1)(3-1)=8=2^3, the no. of distinct prime factors:1
z=7, (7+1)(7-1)=(2^4)3, the no. of distinct prime factors: 2
Looking at the conditions together,
z=3, (3+1)(3-1)=8=2^3, the no. of distinct prime factors:1
z=7, (7+1)(7-1)=(2^4)3, the no. of distinct prime factors: 2.
Therefore, the answer becomes (E).

For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
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Re: Data Sufficiency Pack 4, Question 2) Z is a positive integer...  [#permalink]

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