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Distance-Speed-Time: Anand and Bhim take a trip

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Distance-Speed-Time: Anand and Bhim take a trip  [#permalink]

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New post 13 Jul 2018, 07:18
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Anand and Bhim take a trip in Anand's car. On the first leg of the trip, they drive 80 km per hour to their destination. On the second leg, they turn around and return by the same route in 4 hours. How long do they spend driving on the first leg?

STATEMENT 1:

Their average speed for the entire trip is 70 km per hour.

STATEMENT 2:

The distance to their destination is 240 km.

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Re: Distance-Speed-Time: Anand and Bhim take a trip  [#permalink]

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New post 13 Jul 2018, 08:14
To find how long do Anand and Bhim spend driving on the first leg

Let 'd' be the distance from starting point to the destination and they are driving at 80 km/h4

=> Speed * Time = Distance

=> 80 * t = d

=> \(t = \frac{d}{80}\)

So if we can find the value of 'd' we get the value of 't'

Statement 1

Their average speed for the entire trip is 70 km per hour.

Average speed = \(\frac{Total distance}{Total time}\)

=> 70 = \(\frac{d}{(t + 4)}\)

=> 70 = \(\frac{d}{(d/8 + 4)}\)

From above equation, we get the value of d and hence the value of 't'

Statement 1 is sufficient

Statement 2

The distance to their destination is 240 km.

=> d = 240 and hence we can get the value of 't'

Statement 1 is sufficient alone
Statement 2 is sufficient alone

Hence option D
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Re: Distance-Speed-Time: Anand and Bhim take a trip  [#permalink]

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New post 13 Jul 2018, 09:30
Poor question...
both statements give different answers..
240 km so while going time taken = 240/80=3 hr..

so total time = 3+4 = 7 hr and distance travelled = 240*2/7=480/7 not equal to 70
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Re: Distance-Speed-Time: Anand and Bhim take a trip &nbs [#permalink] 13 Jul 2018, 09:30
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