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Quote:
I do not agree with you. The fact that slope of a line is infinity does not mean that the value of the slope does not exit. The slope of the line x=-1 exits and is greater than 1 and it doesn't cross quadrant I. OA should be E.

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Verdict: vertical lines have NO SLOPE. That is, the concept of slope just doesn't work for vertical lines. The slope doesn't exist!
https://www.purplemath.com/modules/slope.htm

Well I'm afraid the entire math community agrees with me so I'll stick with B.
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The answer lies in the plane of math definitions.
https://en.wikipedia.org/wiki/Slope

"The larger the absolute value of a slope, the steeper the line. A horizontal line has slope 0, a 45° rising line has a slope of +1, and a 45° falling line has a slope of -1. A vertical line's slope is undefined."

I think it origins from a more general math definition: Division by zero.
https://en.wikipedia.org/wiki/Division_(mathematics)

Division by zero (i.e. where the divisor is zero) is not defined.
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walker
The answer lies in the plane of math definitions.
https://en.wikipedia.org/wiki/Slope

"The larger the absolute value of a slope, the steeper the line. A horizontal line has slope 0, a 45° rising line has a slope of +1, and a 45° falling line has a slope of -1. A vertical line's slope is undefined."

I think it origins from a more general math definition: Division by zero.
https://en.wikipedia.org/wiki/Division_(mathematics)

Division by zero (i.e. where the divisor is zero) is not defined.

OG also agree with you guys. What is the source of this question?



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