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SVP
Joined: 07 Nov 2007
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03 Sep 2008, 14:18
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What percent of the MIS students enrolled at Wisconsin University are female?

5% of the female students in Wisconsin University are studying MIS.
12% of the male students in Wisconsin University are studying MIS.

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
EACH statement ALONE is sufficient
Statements (1) and (2) TOGETHER are NOT sufficient

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Senior Manager
Joined: 28 Feb 2007
Posts: 294

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03 Sep 2008, 14:29
E.

let f= # of female students in Wisconsin University
m= # of male students in Wisconsin University

Question says MIS students= 0.05f + 0.12m

0.05f/ (0.05f + 0.12m) doesn't give any real number. E.
Senior Manager
Joined: 31 Jul 2008
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03 Sep 2008, 14:29
E

both the statements dont give any data pertaining to the ratio of males and females with in the MIS
Manager
Joined: 11 Apr 2008
Posts: 198

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03 Sep 2008, 14:33
I think the ans is E

1) 5% of female student of Wisconsin Univ studying in MIS (insuff)
2) 12% of male student of Wisconsin Univ studying in MIS (insuff)
It seems both statements when combined also insuff to find out the ans
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Joined: 09 Jul 2007
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Updated on: 03 Sep 2008, 17:54
IMO E.

5% of the female students in Wisconsin University are studying MIS = > no info about % of female in MIS
12% of the male students in Wisconsin University are studying MIS = > no info about % of female in MIS

combined : .12 x are male in MIS and .05y are female in MIS ; we do not know values of x and Y or ratio of x and y..

Originally posted by ssandeepan on 03 Sep 2008, 14:46.
Last edited by ssandeepan on 03 Sep 2008, 17:54, edited 1 time in total.
VP
Joined: 05 Jul 2008
Posts: 1340

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03 Sep 2008, 17:19
UMB wrote:
E.

let f= # of female students in Wisconsin University
m= # of male students in Wisconsin University

Question says MIS students= 0.05f + 0.12m

0.05f/ (0.05f + 0.12m) doesn't give any real number. E.

This is where I exactly ended up. We dont have any relation between f & M to solve further. Hence E.
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Joined: 07 Nov 2007
Posts: 1738
Location: New York

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03 Sep 2008, 20:12

Yeap easy on.

I overlooked the statements and chose wrong answer.

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Re: ds   [#permalink] 03 Sep 2008, 20:12
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