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26 Jul 2006, 08:38
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hi
Plz help needed on the following exercises
a , b and c are 3 digit integer where a= b+c is the hundred's digit of a equal to the sum of that of b and c
1 The ten digit of a is equal to the ten digit of b + the ten digit of c
2 the unit digit of a is equal to the unit digit of b + the unit digit of c
i found each insufficient but i am stuck to study both statement together
plz post detail explanation and reasoning
thanks
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26 Jul 2006, 10:01
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mand-y
a = 100x + 10y + z
b = 100p + 10q + r
c = 100m + 10n + o
a = b+c
a = 100p + 10q + r + 100m + 10n + o
a = 100 (p+m) + 10 (q+n) + (r + o)
from i, y = q+n, a = 100 (p+m) + 10 y + (r + o). now x = (p+m) and z = (r + o) because (r+o) cannot exceds 10.
from ii, z = (r + o), a = 100 (p+m) + 10 (q+n) + z. now x and y may or may not respectively equal to (p+m) and (q+n).
suppose a = 865, b = 223, and c = 742. a = b+c and sum of tens digits of b and c are equal are equal to the same of a but not the hundred digit of a may necesserily not equal to the same of b and c.
i go with A.
26 Jul 2006, 13:38
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A
a = xyz
b = pqr
c = mno
St1: y = q+n that means q+n is less than equal to 9. This is true only when (r+o) is also less than equal to 9. To keep a,b,c 3 digit numbers (p+m) must be less than 9 hence x = p+m: SUFF
St2: z = r +o means r+o will be than equal to 9. But this does not guarantee q+n less than 9. If q+n is greater than 9 then p+m will not be equal to x otherwise it will be equal.: INSUFF
a = xyz
b = pqr
c = mno
St1: y = q+n that means q+n is less than equal to 9. This is true only when (r+o) is also less than equal to 9. To keep a,b,c 3 digit numbers (p+m) must be less than 9 hence x = p+m: SUFF
St2: z = r +o means r+o will be than equal to 9. But this does not guarantee q+n less than 9. If q+n is greater than 9 then p+m will not be equal to x otherwise it will be equal.: INSUFF
