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# ds -distinct integers

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Joined: 07 Nov 2007
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04 Sep 2008, 13:18
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If a, b, and c are positive distinct integers, is $$(a/b)/c$$ an integer?

c = 2
a = b + c

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
EACH statement ALONE is sufficient
Statements (1) and (2) TOGETHER are NOT sufficient
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04 Sep 2008, 13:30
St. 2 (a/b)/c = (b+c)/bc = 1/c + 1/b. Since b and c are distinct integers, this sum cannot be an integer.-- sufficient

St. 1 No information about a and b-- Insufficient.

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Senior Manager
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04 Sep 2008, 14:30
how about if 1/b= .7 and 1/c=.3 in that case 1/b +1/c = 1 (integer)

ans shud be C

as 1/c = .5 and the other has to be something apart from .5

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04 Sep 2008, 14:43
I agree with B .

Excellent reasoning KASSALMD.

stallone,

for the expression 1/b +1 / c : for any valuse of b , c > 2 , the expression is < 1 ;

if b=1 and c=2 => 1/b +1 / c = 1.5 ; llly for no integer valuse of b and c the expression will be 1 ( greater integer valuse of 1/b +1 / c is out of question, as that is possible only when b,c=1)

so it can not be an integer.

We do not have any integer b or c which satify 1/b= .7 and 1/c=.3

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04 Sep 2008, 20:50
good approach KASSALMD !!

OA is B
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Re: ds -distinct integers   [#permalink] 04 Sep 2008, 20:50
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