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ds -distinct integers

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SVP
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ds -distinct integers [#permalink]

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New post 04 Sep 2008, 13:18
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If a, b, and c are positive distinct integers, is \((a/b)/c\) an integer?

c = 2
a = b + c

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
EACH statement ALONE is sufficient
Statements (1) and (2) TOGETHER are NOT sufficient
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Re: ds -distinct integers [#permalink]

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New post 04 Sep 2008, 13:30
B is the answer.
St. 2 (a/b)/c = (b+c)/bc = 1/c + 1/b. Since b and c are distinct integers, this sum cannot be an integer.-- sufficient

St. 1 No information about a and b-- Insufficient.

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New post 04 Sep 2008, 14:30
how about if 1/b= .7 and 1/c=.3 in that case 1/b +1/c = 1 (integer)


ans shud be C

as 1/c = .5 and the other has to be something apart from .5

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New post 04 Sep 2008, 14:43
I agree with B .

Excellent reasoning KASSALMD.

stallone,

for the expression 1/b +1 / c : for any valuse of b , c > 2 , the expression is < 1 ;

if b=1 and c=2 => 1/b +1 / c = 1.5 ; llly for no integer valuse of b and c the expression will be 1 ( greater integer valuse of 1/b +1 / c is out of question, as that is possible only when b,c=1)

so it can not be an integer.

We do not have any integer b or c which satify 1/b= .7 and 1/c=.3

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Kudos [?]: 1057 [0], given: 5

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Re: ds -distinct integers [#permalink]

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New post 04 Sep 2008, 20:50
good approach KASSALMD !!


OA is B
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Re: ds -distinct integers   [#permalink] 04 Sep 2008, 20:50
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