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Piter
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Good question... need more of this kind.

Ans: C
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ywilfred
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I go with B.
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trivikram
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ywilfred
I go with B.


It could be in III quadrant where A could be less than B but at the same time B<0.

So I think C is correct
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Artemov
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The slope will be b/a
The line passes through the origin. It will have value of -x, y in quadrant II and x, -y in quadrant IV.
Combining the two statements, it can be deduced that the point a,b is in quadrant II.
The answer is C.

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GMATBLACKBELT
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ds

S1:
slope of line k is negative. So the slope can be -a/b or a/-b.

Insuff.


S2: a<b

Doesnt help us. too many options for a and b.

Together.

since S1 says that a or b must be negative and S2 says a<b. a must be the negative number. So b is positive.

C.


Much better than the XY plane Q i got on my GMATPrep...



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