sharadGmat
ps_dahiya
Even though the answer should be C in this case but we should keep the following thing in mind.
Taking the same question:
For the max value of expression we can not take the max value of x because in the main term x is not linear. x is raised to the power two.
I will give you an example.
-5<=x<=1/2
1/2<=y<=1
Take max values of x and y to find M. We get M = 5/4
Take min values of x and y to find N. We get N = 202
Which one is MAX?
If the equation is linear then equation will have max value at the max of all variables and min value at min of all variables.
This is really very tricky qn..
Answer is B.
Here is the OE:
Since X varies from +ve to -ve , the value of x^2 is minimum when x^2 is zero.
So Min =N= (0+y)/y=1
Max =M= (5^2+7)/7.
So we can find M-N..

Hmmm... I disagree with (B). Let me elaborate.
Ok, from Stem2 we know -2<=x<=5 and y<=7.
I agree that Min=N=(0+y)/y=1 happens when x=0
But it is not true that Max=M= (5^2+7)/7=32/7 is the max!
Easy to see: just take y=1, x=5 then M=(25+1)/1=26 (greater than 32/7)
And if you take y=1/2, it will be even larger
And if you take y=0.01, it will be even larger
and so on
The M (Max) will approach infinity as y approaches 0. Since from Stem2 we don't know what the lower limit of y, Max can be anything!
Therefore we can not determine Max-Min from Stem2
In my mind, the answer should be (C).
Anybody agrees?