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04 Aug 2004, 01:46
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Hi all
any guess on this? Please read it very carefully before you answer!!
The town rules in Kid-Town require each house to have at least a ping-pong table or a soccer-table. If there are 50 houses in Kid-Town, how many houses carry both types of tables?
(1) The number of houses that have a ping-pong table only is 20.
(2) The number of houses that have a soccer table is 40.
any guess on this? Please read it very carefully before you answer!!
The town rules in Kid-Town require each house to have at least a ping-pong table or a soccer-table. If there are 50 houses in Kid-Town, how many houses carry both types of tables?
(1) The number of houses that have a ping-pong table only is 20.
(2) The number of houses that have a soccer table is 40.
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04 Aug 2004, 03:23
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I don't really understand this question.
A, B and D are clearly out. Consider C and E.
Take x as the number of houses which carry both types of tables.
From (1) we have: the number of houses with a ping-pong table = 20 + x
From (2) we have: the number of houses with a soccer table = 40 = x + the number of houses with a soccer table only.
From (1) and (2) we have: 20 + x + 40 - x = 50 unreasonable. Anyone can explain???
A, B and D are clearly out. Consider C and E.
Take x as the number of houses which carry both types of tables.
From (1) we have: the number of houses with a ping-pong table = 20 + x
From (2) we have: the number of houses with a soccer table = 40 = x + the number of houses with a soccer table only.
From (1) and (2) we have: 20 + x + 40 - x = 50 unreasonable. Anyone can explain???
04 Aug 2004, 06:30
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I have the same problem.
taking them together, I've built the venn diagram, and put an x in the center, a y in the "soccer table only" side, and 20 in the "ping pong only" side. That means that x+y must equal 40, and 20+x+y must equal 50.
That just doesn't compute.
I'm assuming that there are exactly 50 houses, and each one has at least one, since the law makes it clear that that must be so.
Surya_s, what did you mean by "read it carefully before you answer"?
taking them together, I've built the venn diagram, and put an x in the center, a y in the "soccer table only" side, and 20 in the "ping pong only" side. That means that x+y must equal 40, and 20+x+y must equal 50.
That just doesn't compute.
I'm assuming that there are exactly 50 houses, and each one has at least one, since the law makes it clear that that must be so.
Surya_s, what did you mean by "read it carefully before you answer"?
