Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 2206:30 AM PST
-08:30 AM PST
Let’s dive deep into advanced CR to ace GMAT Focus! Join this webinar to unlock the secrets to conquering Boldface and Paradox questions with expert insights and strategies. Elevate your skills and boost your GMAT Verbal Score now!
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
24 Jul 2019, 00:26
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
73% (01:26) correct
27%
(01:06)
wrong
based on 78
sessions
History
Date
Time
Result
Not Attempted Yet
If \(\sqrt{Z}\) is greater than 0, is \(\sqrt{Z}\) greater than Z ?
(1) Z is greater than zero
(2) \(\sqrt{Z}\) is less than 1
(1) Z is greater than zero
(2) \(\sqrt{Z}\) is less than 1
firas92
Current Student
Joined: 16 Jan 2019
Last visit: 02 Dec 2024
Posts: 616
Own Kudos:
Given Kudos: 142
Location: India
Concentration: General Management
Schools: Tepper '23 (M$) Foster '23 (D)
GMAT 1: 740 Q50 V40
WE:Sales (Other)
Products:
24 Jul 2019, 00:52
Kudos
Bookmarks
If \(\sqrt{Z}>0\), then \(Z>0\),
If \(Z<1\), then \(\sqrt{Z}>Z\)
If \(Z>1\), then \(\sqrt{Z}<Z\)
So, we need to know if \(0<Z<1\)
1. \(Z\) is greater than zero
We already know this from the stem.
If \(Z<1\), then \(\sqrt{Z}>Z\)
If \(Z>1\), then \(\sqrt{Z}<Z\)
1 is insufficient
2. \(\sqrt{Z}\) is less than 1
If \(\sqrt{Z}<1\), \(Z<1\)
So, if \(Z<1\), then \(\sqrt{Z}>Z\)
We have an answer
2 is sufficient
Answer is (B)
If \(Z<1\), then \(\sqrt{Z}>Z\)
If \(Z>1\), then \(\sqrt{Z}<Z\)
So, we need to know if \(0<Z<1\)
1. \(Z\) is greater than zero
We already know this from the stem.
If \(Z<1\), then \(\sqrt{Z}>Z\)
If \(Z>1\), then \(\sqrt{Z}<Z\)
1 is insufficient
2. \(\sqrt{Z}\) is less than 1
If \(\sqrt{Z}<1\), \(Z<1\)
So, if \(Z<1\), then \(\sqrt{Z}>Z\)
We have an answer
2 is sufficient
Answer is (B)
24 Jul 2019, 01:28
Kudos
Bookmarks
If √Z is greater than 0, is √Z greater than Z ?
(1) Z is greater than zero
(2) √Z is less than 1
We have √Z > 0. √Z > Z ?
Statement 1) Z > 0
Since both √Z and Z are greater than 0, it is possible that
√Z > Z OR Z >√Z (Yes and No both possibilities).
INSUFFICIENT.
Statement 2) √Z < 1
From question stem we have √Z > 0
0 < √Z < 1
Z is a fraction less than 1
Let’s take √Z = ¼
Z = 1/16
√Z > Z
OR
√Z = ½
Z = ¼
√Z > Z again
SUFFICIENT.
Answer (B)
(1) Z is greater than zero
(2) √Z is less than 1
We have √Z > 0. √Z > Z ?
Statement 1) Z > 0
Since both √Z and Z are greater than 0, it is possible that
√Z > Z OR Z >√Z (Yes and No both possibilities).
INSUFFICIENT.
Statement 2) √Z < 1
From question stem we have √Z > 0
0 < √Z < 1
Z is a fraction less than 1
Let’s take √Z = ¼
Z = 1/16
√Z > Z
OR
√Z = ½
Z = ¼
√Z > Z again
SUFFICIENT.
Answer (B)
