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chunjuwu
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DS2320 30 Jul 2004, 08:19
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please give me a hand, thank you.



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Dookie
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DS2320 31 Jul 2004, 05:43
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I think it's D.

Those are regular hexagons.

The area of a regular hexagon is (3*sqrt(3)/2)*X^2, where X is the side of the hexagon.

To calculate the total requested area you only need to be able to calculate
the area of one hexagon.

Using statement 1 or 2 alone you can do that.
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DS2320 31 Jul 2004, 12:28
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Dookie is right...either statement alone is sufficient and D is the final answer. The easiest way to approach the problem is to draw a straight line right in the middle of the tile both horizontally and vertically. you'll then be able to figure it out easily. Remember that the Hexagon has 6 equilateral triangles. With this info int would be easy to figure it out.
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ian7777
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DS2320 03 Aug 2004, 08:32
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I have a few things to say about this problem.

1. Yes, it is a real problem.

2. THE TRAP OF C SHOULD BE SCREAMING AT YOU. In this problem, they want the area of a rectangular piece. If you have the length, and you have the width, you can answer the question. Putting both of the answers together, THAT'S EXACTLY WHAT YOU GET! No way am I ever going to choose C in that condition. Too easy. F.U. ETS, not fallin' for that one :fu . I'm going deeper. If I had to guess right off the starting block, I'd say D and move on, because there's no difference what each one is telling us, meaning, whatever the solution, we should be able to apply it in the same with with the width and the length.

3. Any perfect hexagon is, well, perfect. All the sides are equal and all the angles are 120 degrees. If we divide one up, it'll be composed of a bunch of perfect equilateral triangels, where all the sides are equal. Take a look at this:



So the line down the middle is exactly twice the length of the side, and from the blue outside triangle I drew, we can know the sides of the spaces outside the hexagons, all in terms of x.

Since it's all in terms of x, we can add them all up the pieces of the length, or of the width, and either way, if we knew either side, we'd have everything we need to solve.



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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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