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During one month at a particular restaurant, 1/6 of the burgers so

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Joined: 11 Feb 2015
Posts: 1146
During one month at a particular restaurant, 1/6 of the burgers so  [#permalink]

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New post 29 Mar 2020, 19:14
3
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

66% (01:50) correct 34% (02:21) wrong based on 56 sessions

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During one month at a particular restaurant, 1/6 of the burgers sold were turkey burgers and 1/4 of the rest of the burgers sold were beef. If x of the burgers sold were beef, how many were turkey burgers?

A) \(\frac{x}{8}\)
B) \(\frac{x}{2}\)
C) \(\frac{2x}{3}\)
D) \(\frac{3x}{4}\)
E) \(\frac{4x}{5}\)

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Joined: 04 Jan 2015
Posts: 3394
Re: During one month at a particular restaurant, 1/6 of the burgers so  [#permalink]

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New post 30 Mar 2020, 02:43
3

Solution



Given
In this question, we are given that
    • During one month at a particular restaurant, \(\frac{1}{6}\) of the burgers sold were turkey burgers and \(\frac{1}{4}\) of the rest of the burgers sold were beef.
    • Also, x of the burgers sold were beef.

To find
We need to determine
    • Number of turkey burgers sold

Approach and Working out
If we assume N to be the total number of burgers, then
    • Number of turkey burgers sold = \(\frac{N}{6}\)

Remaining burgers = \(N – \frac{N}{6} = \frac{5N}{6}\)
    • Number of beef burgers sold = \(\frac{5N}{6} * \frac{1}{4} = \frac{5N}{24}\)

As per the given condition, \(\frac{5N}{24} = x\)
    Or, \(N = \frac{24x}{5}\)

Hence, number of turkey burgers sold = \(\frac{N}{6} = \frac{24x}{5} * \frac{1}{6} = \frac{4x}{5}\)

Thus, option E is the correct answer.

Correct Answer: Option E
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Joined: 26 Apr 2019
Posts: 159
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Concentration: Finance, Leadership
GMAT 1: 690 Q49 V34
GMAT 2: 700 Q49 V36
GMAT 3: 720 Q50 V37
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Re: During one month at a particular restaurant, 1/6 of the burgers so  [#permalink]

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New post 06 Apr 2020, 02:04
let y be the total number of burger then turkey burger will be y/6 and beef burger will be 5y/24 =x as given in question so y =24x/5
thus total number of turkey burger in form of x will be 4x/5
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Re: During one month at a particular restaurant, 1/6 of the burgers so   [#permalink] 06 Apr 2020, 02:04

During one month at a particular restaurant, 1/6 of the burgers so

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