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netcaesar
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LM
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total males =M
total females =F
total interns = (M+F)
total number of correctional facilities = n
Each has no. of interns = (M+F)/n
Each has no. of females = (22/100)*F
Each has male interns = x such that => (18/100)*M < x < (22/100)*M
(M+F)/n = (22/100)*F + x

x= (M+F)/n - (22/100)*F

(18/100)*M < (M+F)/n - (22/100)*F < (22/100)*M

how do you get n = 5?

in this case each correctional facility has (M+F)/n interns, but that does not mean each has M/n and F/n interns.

M can be 100, F can be 5 and vice versa!

Could you please explain in detail?
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maratikus
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LM

Each has no. of interns = (M+F)/n
Each has no. of females = (22/100)*F
Each has male interns = x such that => (18/100)*M < x < (22/100)*M
Could you please explain in detail?

LM, it's not "each" but only one correctional facility. One particular correctional facility has 22% of female interns (22/100)*F and has d*M males -> total number of interns in the facility is (22/100)*F + d*M. Since each facility has the same total number of interns (F+M)/((22/100)*F + d*M) has to be a positive integer. Using inequalities I showed that the integer is greater than 4 and less than 6. It has to be equal to 5. Since there are more than 1/5 female interns, d < 1/5, otherwise the facility will have more than 1/5 of all interns which contradicts the condition that each facility has the same number of interns.
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netcaesar
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You are right.

OA is D



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