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Question Stats:
50% (03:50) correct
50%
(02:19)
wrong
based on 6
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Each lunch customer at Regina’s orders one of three set lunch menus, priced at €19, €29, and €49. Yesterday, x of Regina’s n lunch customers ordered the €49 menu, and y more customers ordered the €19 menu than ordered either of the two more expensive menus. What was Regina’s lunch revenue yesterday?
A) 24n + 20x + 5y
B) 24n + 20x − 10y
C) 24n + 20x − 5y
D) 29n + 30x − 10y
E) 29n + 30x − 5y
A) 24n + 20x + 5y
B) 24n + 20x − 10y
C) 24n + 20x − 5y
D) 29n + 30x − 10y
E) 29n + 30x − 5y
21 Sep 2026, 23:34
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22 Sep 2026, 05:56
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If x = y = 0, the number of customers ordering the €19 menu equals the number ordering the €29 menu. Therefore, the average amount spent per customer is (19 + 29)/2 = 24, so the total revenue would be 24n.
Now make the two adjustments.
Since there are y more customers ordering the €19 menu than either of the two more expensive menus, y/2 customers are effectively transferred from the €29 menu to the €19 menu.
Each transfer decreases revenue by 29 − 19 = 10.
Thus, the total decrease is 10(y/2) = 5y.
Also, x customers are transferred from the €29 menu to the €49 menu.
Each transfer increases revenue by 49 − 29 = 20.
Thus, the total increase is 20x.
Therefore, Regina’s total lunch revenue is 24n + 20x − 5y.
Now make the two adjustments.
Since there are y more customers ordering the €19 menu than either of the two more expensive menus, y/2 customers are effectively transferred from the €29 menu to the €19 menu.
Each transfer decreases revenue by 29 − 19 = 10.
Thus, the total decrease is 10(y/2) = 5y.
Also, x customers are transferred from the €29 menu to the €49 menu.
Each transfer increases revenue by 49 − 29 = 20.
Thus, the total increase is 20x.
Therefore, Regina’s total lunch revenue is 24n + 20x − 5y.
