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07 Dec 2012, 10:08
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Each of the letters in the table above represents one of the numbers 1, 2, or 3, and each of these numbers occurs exactly once in each row and exactly once in each column. What is the value of r? (1) v + z = 6 (2) s + t + u + x = 6 Attachment:
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Each of the letters in the table above represents one of the numbers 1, 2, or 3, and each of these numbers occurs exactly once in each row and exactly once in each column. What is the value of r?(1) v + z = 6. Since v and z are 1, 2, or 3, then v=z=3. So, we have 3 in the second and third columns, which mean that neither s nor t can be 3, which means that r must be 3. Sufficient. (2) s + t + u + x = 6. We can have two combinations of the numbers to satisfy s + t + u + x = 6: 1+1+1+3=6 OR 1+1+2+2=6. The first case is not possible since in this case three letters out of s, t, u and x would be 1, which would mean that either in the first row or in the first column we have the same number 1. So, we have 1+1+2+2=6 case, which means that r must be 3 (since no other number in the first column or the first row is 3). Sufficient. Answer: D. Attachment:
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Attachment:
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For the seconds statement, I thought of it like this r + u + x = 6 r + s + t = 6 2r + u + x + s + t = 12 2r+6=12 (Since, s+t+u+x=6) 2r=6 r=3
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Walkabout wrote: Attachment: Table.png Each of the letters in the table above represents one of the numbers 1, 2, or 3, and each of these numbers occurs exactly once in each row and exactly once in each column. What is the value of r? (1) v + z = 6 (2) s + t + u + x = 6 For St 1, we are given that v+z=6...since possible nos are only 1,2 and 3, we can conclude that v=z=3. Since v and z are in row 2 and row 3 then number 3 in row 1 has to be at position of r > r= 3. Cancelling option B, C and E From st 2, we have s+t+u+x= 6 and 2r+s+u+t+x= 12....solving for r we get r>3 Hence ans should be D
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Re: Each of the letters in the table above represents one of the [#permalink]
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17 Dec 2015, 07:55
Answer is D. Please see my solution below:
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Re: Each of the letters in the table above represents one of the [#permalink]
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05 Aug 2016, 10:43
Walkabout wrote: Each of the letters in the table above represents one of the numbers 1, 2, or 3, and each of these numbers occurs exactly once in each row and exactly once in each column. What is the value of r? (1) v + z = 6 (2) s + t + u + x = 6 Target question: What is the value of r?Statement 1: v+z = 6Step 1: If v+z=6, then v and z must both equal 3. Step 2: If each number occurs exactly once in each row and exactly once in each column, then s cannot equal 3 (since s and v are in the same column) and t cannot equal 3 (since t and z are in the same column). Step 3: If s and t cannot equal 3, then r must equal 3 (since each number occurs exactly once in each row) Since we can answer the target question with certainty, statement 1 is SUFFICIENT Statement 2 s+t+u+x = 6: If each number occurs exactly once in each row and exactly once in each column, the sum of numbers in any row or column will always equal 6. So, r+s+t=6, and r+u+x=6 When we combine these two equations, we get (r+s+t)+ (r+u+x)= 6+6 Simplify to get: 2r+(s+t+u+x)=12 Statement 2 tells us that s+t+u+x=6 When we add this to the equation 2r+(s+t+u+x)=12, we get: 2r+(6)=12 When we solve this, we get r=3Since we can answer the target question with certainty, statement 2 is SUFFICIENT Answer = Cheers, Brent
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Re: Each of the letters in the table above represents one of the [#permalink]
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10 Sep 2016, 07:35
Walkabout wrote: Each of the letters in the table above represents one of the numbers 1, 2, or 3, and each of these numbers occurs exactly once in each row and exactly once in each column. What is the value of r? (1) v + z = 6 (2) s + t + u + x = 6 1. v+z = 6, which is possible only for 3+3 since there is one 3, in middle and last colomn, the only possible value for r is 3....sufficient 2. s + t + u + x = 6....this is possible for combinations, 1+2 + 1+2 or 2+1 + 1+2 and so on....as each number should occur only once, r has to take value of 3...sufficient so answer is D
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Re: Each of the letters in the table above represents one of the [#permalink]
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15 Apr 2017, 02:11
m0h1t wrote: For the seconds statement, I thought of it like this
r + u + x = 6 r + s + t = 6
2r + u + x + s + t = 12 2r+6=12 (Since, s+t+u+x=6) 2r=6 r=3 I guess another good way to think about these problems is in terms of max., min., and extreme values. i.e. min. value of s+t = 3 and min. value of u+x = also 3 > and the only way to get 3 from s+t or 3 from u+x is by adding 2+1 therefore r must be 3
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06 Aug 2017, 22:20
This is how I approached it  S1: Just thought  if there are two integers which can take value of 1 or 2 or 3 and the their sum is 6, what is the value of each integer?  it took few seconds to realize that both have to be 3. Meaning V = Z = 3. This also means that U and X cannot be 3 (this follows from the stem). This again means R MUST be 3. Suff S2: Here I used Algebra. We have R+S+T = 6 and R+U+X = 6. Adding both you get 2R+S+T+U+X = 12. We can see that the Value in S2 can be substituted to get the value of R. Suff Both statements individually sufficient. Answer is D PS: People who have played Sudoku will find this one easier to tackle
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