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# Each of the marbles in a bag is either blue, red, or green, and there

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Re: Each of the marbles in a bag is either blue, red, or green, and there [#permalink]
Bunuel wrote:
Each of the marbles in a bag is either blue, red, or green, and there is at least one marble of each color in the bag. If the bag contains twice as many blue marbles as red marbles, then the number of red marbles in the bag divided by the total number of marbles in the bag is

A. less than 1/3
B. equal to 1/3
C. between 1/3 and 1/2
D. between 1/2 and 2
E. greater than 2

Since we need to consider a common approach, the best will be to assume the least number of marbles.
R=1,B=2,G=1

R=1/4, which is less than 1/3.

Hence A
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Re: Each of the marbles in a bag is either blue, red, or green, and there [#permalink]
Bunuel wrote:
Each of the marbles in a bag is either blue, red, or green, and there is at least one marble of each color in the bag. If the bag contains twice as many blue marbles as red marbles, then the number of red marbles in the bag divided by the total number of marbles in the bag is

A. less than 1/3
B. equal to 1/3
C. between 1/3 and 1/2
D. between 1/2 and 2
E. greater than 2

Let’s let r = the number of red marbles, b = the number of blue marbles, and g = the number of green marbles. We also know that b = 2r. So the ratio of red marbles to the total number of marbles is r/(r + 2r + g) = r/(3r + g), which is less than r/(3r) or 1/3.