Let Original admission fee= x
Original number of people = n
1 xn =(x-.75)(n+100)
=>100x - .75 n = 75 ---1
Not sufficient .
2.The second statement should have been
If the admission fee had been 1.50$
more and 100 fewer people had attended, the club would have received the same amount in admission fee
xn= (x+1.5)(n-100)
=> 100x - 1.5 n = -150 ---2
Not sufficient .
Combining 1 and 2 , we get 2 distinct linear equations with 2 unknowns
n=300
x=3
Answer C
If the admission fee had been 1.50$
less and 100 fewer people had attended, the club would have received the same amount in admission fee Then,
xn= (x-1.5)(n-100)
=> 100x +1.5n = 150 --3
On solving 1 and 3 , we get
x=1
n=33.33
We can even see that statement 2 has an issue by analyzing that for a product xn to remain same if one of the values increase , the other should decrease . The product won't be same if both the values decrease or increase .
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