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Each person who attended a company meeting was either a

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Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both. If 62 percent of these who attended the meeting were stockholders and 47 percent were employees. What percent were stockholders, who were not employees?

A. 52
B. 53
C. 54
D. 55
E. 56
[Reveal] Spoiler: OA

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Re: Each person who attended a company meeting [#permalink]

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New post 26 Apr 2012, 03:58
100 = 62 + 47 - n(SnE) [where n represents intersection]
=> n(SnE) = 9

=> Number who were only stockholders = n(S) - n(SnE) = 53 percent

Option (B)
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monir6000 wrote:
Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both. If 62 percent of these who attended the meeting were stockholders and 47 percent were employees. What percent were stockholders, who were not employees?

A. 52
B. 53
C. 54
D. 55
E. 56


Total = Stockholders + Employees - Both;
100 = 62 + 47 - Both --> Both = 9;

Percent of stockholders, who were not employees is: Stockholders - Both = 62 - 9 =53.

Answer: B.
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New post 01 Dec 2015, 09:18
I came up with the same answer choice B, but my approach was slightly different!

47% were employees which shall cover those who were only employees and those who were both shareholders and employees.

Thus, the number of attendants who were only shareholders is 100% - 47% = 53%.

Correct me if I'm wrong please!!!

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Re: Each person who attended a company meeting was either a [#permalink]

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New post 01 Dec 2015, 10:32
Charles_River wrote:
I came up with the same answer choice B, but my approach was slightly different!

47% were employees which shall cover those who were only employees and those who were both shareholders and employees.

Thus, the number of attendants who were only shareholders is 100% - 47% = 53%.

Correct me if I'm wrong please!!!


USe venn diagram , matter of 5 secods
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Untitled.png [ 4.23 KiB | Viewed 4656 times ]


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New post 20 Jul 2016, 05:13
Does anyone know how can we solve this question by using the matrix/table ? I'm having difficulties in drawing one.

Thanks for your help!

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New post 28 Jul 2016, 13:02
HarveyKlaus wrote:
Does anyone know how can we solve this question by using the matrix/table ? I'm having difficulties in drawing one.

Thanks for your help!


Image

HarveyKlaus Hope it helps. This is my first post!

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Here we can use some of our high school set theory =>
N(A U B) = 100=> N(A) = 62 ; N(B)=47
N(intersection) => 62+47-100=9
Only A=>62-9=>53
Smash B
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Each person who attended a company meeting was either a [#permalink]

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New post 13 Aug 2017, 10:17
I too used the Double Matrix Approach to solve this.

The Key thing here is to pay attention to - "Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both.".

What this means is there is no one in the Meeting who is neither a Shareholder NOR an employee.

Once this is know the double Matrix can be written quickly. This is already mentioned by one of the users above.
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Last edited by susheelh on 03 Sep 2017, 21:38, edited 1 time in total.

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Re: Each person who attended a company meeting was either a [#permalink]

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New post 03 Sep 2017, 19:07
Abhishek009 wrote:
Charles_River wrote:
I came up with the same answer choice B, but my approach was slightly different!

47% were employees which shall cover those who were only employees and those who were both shareholders and employees.

Thus, the number of attendants who were only shareholders is 100% - 47% = 53%.

Correct me if I'm wrong please!!!


USe venn diagram , matter of 5 secods



Abhishek009

Abhishek - Could you explain how you arrived at this Venn diagram, please?

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Each person who attended a company meeting was either a [#permalink]

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New post 03 Sep 2017, 19:36
susheelh wrote:
I too used the Double Matrix Approach to solve this.

The Key thing here is to pay attention to - "Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both.".

What this means is there is no one in the Meeting who is neither a Shareholder OR an employee.

Once this is know the double Matrix can be written quickly. This is already mentioned by one of the users above.


OK, still figuring out how I could solve this. I came across a video tut on here to solve questions using double matrix method. In that context, susheel - did you mean NEITHER a stockholder NOR an employee?

GMATPrepNow - Could you help me with the double matrix table as you explained in one of your videos, please?

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Hello Blackbox!

Yes, thats correct! I will go and edit the typo. Thanks for pointing it out :-)

Here's the double Matrix. Just to make it clearer.

Attachment:
Screen Shot 2017-09-04 at 9.51.17 AM.png
Screen Shot 2017-09-04 at 9.51.17 AM.png [ 20.73 KiB | Viewed 531 times ]


We choose 100 as the smart number since everything is in percentage (Its marked in Orange in the screen shot). The Green colour is what is "Given"in the question. Rest everything is simple addition. Finally we get the required answered (Marked in Yellow).


Blackbox wrote:
susheelh wrote:
I too used the Double Matrix Approach to solve this.

The Key thing here is to pay attention to - "Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both.".

What this means is there is no one in the Meeting who is neither a Shareholder OR an employee.

Once this is know the double Matrix can be written quickly. This is already mentioned by one of the users above.


OK, still figuring out how I could solve this. I came across a video tut on here to solve questions using double matrix method. In that context, susheel - did you mean NEITHER a stockholder NOR an employee?

GMATPrepNow - Could you help me with the double matrix table as you explained in one of your videos, please?

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Re: Each person who attended a company meeting was either a [#permalink]

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New post 04 Sep 2017, 18:48
Thank you, susheelh. Job well done at explaining! I intend to follow this approach for overlapping sets :) ... although, I am yet to encounter a problem where there are more than 2 sets that overlap.

+1 to your solution!

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New post 04 Sep 2017, 18:55
I am Glad that it helped!

There are loads of question with more then two sets overlap, I am sure you will find them.

As a general thumb rule (courtesy : MGMAT strategy guides) : for two set overlap use double matrix. For 3 set overlap, use Venn diagrams.



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Re: Each person who attended a company meeting was either a [#permalink]

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New post 04 Sep 2017, 19:22
susheelh wrote:
... As a general thumb rule (courtesy : MGMAT strategy guides) : for two set overlap use double matrix. For 3 set overlap, use Venn diagrams.


I was thinking about the same as well. Like I said, I have not yet started working on Overlapping Sets questions just yet to evaluate the two approaches :) Thanks, bud!

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Re: Each person who attended a company meeting was either a   [#permalink] 04 Sep 2017, 19:22
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