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Each person who attended a company meeting was either a [#permalink]

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26 Apr 2012, 03:51

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Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both. If 62 percent of these who attended the meeting were stockholders and 47 percent were employees. What percent were stockholders, who were not employees?

Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both. If 62 percent of these who attended the meeting were stockholders and 47 percent were employees. What percent were stockholders, who were not employees?

A. 52 B. 53 C. 54 D. 55 E. 56

Total = Stockholders + Employees - Both; 100 = 62 + 47 - Both --> Both = 9;

Percent of stockholders, who were not employees is: Stockholders - Both = 62 - 9 =53.

Re: Each person who attended a company meeting was either a [#permalink]

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24 Aug 2015, 21:59

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Re: Each person who attended a company meeting was either a [#permalink]

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29 Jul 2016, 10:42

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Here we can use some of our high school set theory => N(A U B) = 100=> N(A) = 62 ; N(B)=47 N(intersection) => 62+47-100=9 Only A=>62-9=>53 Smash B
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30 Jul 2017, 10:37

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Each person who attended a company meeting was either a [#permalink]

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13 Aug 2017, 10:17

I too used the Double Matrix Approach to solve this.

The Key thing here is to pay attention to - "Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both.".

What this means is there is no one in the Meeting who is neither a Shareholder NOR an employee.

Once this is know the double Matrix can be written quickly. This is already mentioned by one of the users above.
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Last edited by susheelh on 03 Sep 2017, 21:38, edited 1 time in total.

Each person who attended a company meeting was either a [#permalink]

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03 Sep 2017, 19:36

susheelh wrote:

I too used the Double Matrix Approach to solve this.

The Key thing here is to pay attention to - "Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both.".

What this means is there is no one in the Meeting who is neither a Shareholder OR an employee.

Once this is know the double Matrix can be written quickly. This is already mentioned by one of the users above.

OK, still figuring out how I could solve this. I came across a video tut on here to solve questions using double matrix method. In that context, susheel - did you mean NEITHER a stockholder NOR an employee?

GMATPrepNow - Could you help me with the double matrix table as you explained in one of your videos, please?

Yes, thats correct! I will go and edit the typo. Thanks for pointing it out

Here's the double Matrix. Just to make it clearer.

Attachment:

Screen Shot 2017-09-04 at 9.51.17 AM.png [ 20.73 KiB | Viewed 531 times ]

We choose 100 as the smart number since everything is in percentage (Its marked in Orange in the screen shot). The Green colour is what is "Given"in the question. Rest everything is simple addition. Finally we get the required answered (Marked in Yellow).

Blackbox wrote:

susheelh wrote:

I too used the Double Matrix Approach to solve this.

The Key thing here is to pay attention to - "Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both.".

What this means is there is no one in the Meeting who is neither a Shareholder OR an employee.

Once this is know the double Matrix can be written quickly. This is already mentioned by one of the users above.

OK, still figuring out how I could solve this. I came across a video tut on here to solve questions using double matrix method. In that context, susheel - did you mean NEITHER a stockholder NOR an employee?

GMATPrepNow - Could you help me with the double matrix table as you explained in one of your videos, please?

Re: Each person who attended a company meeting was either a [#permalink]

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04 Sep 2017, 18:48

Thank you, susheelh. Job well done at explaining! I intend to follow this approach for overlapping sets ... although, I am yet to encounter a problem where there are more than 2 sets that overlap.

Re: Each person who attended a company meeting was either a [#permalink]

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04 Sep 2017, 19:22

susheelh wrote:

... As a general thumb rule (courtesy : MGMAT strategy guides) : for two set overlap use double matrix. For 3 set overlap, use Venn diagrams.

I was thinking about the same as well. Like I said, I have not yet started working on Overlapping Sets questions just yet to evaluate the two approaches Thanks, bud!

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