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kevincan
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1. The area of the semicircle = 1/2 * pi * (EC/2)^2 > 40
EC > 8 * sqrt (5/pi)

Area of the triangle = 1/2 * AC * BC = 1/2 BC^2 ( isoceles triangle)

BC = EC + ? say 1
then area of the triangle = 1/2 * (8* sqrt(5/pi) + 1)^2 < 80
if BC = EC + 3 then area of triangle > 80 INSUFF

1. BE is > 2 . by itself INSUFF

combined: SUFF so C

Kevincan, is there an easier way to approach the math?
It took me more than 2 minutes to do the calculation..
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haas_mba07
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Answer: A
Q: Area of ABC > 80

As isosceles triangle :
AC= BC = a

1/2 x a x a > 80

or a^2 > 160

S1: Given Area of semicircle > 40

pi x r x r > 2 x 40
or r x r > 2 x 40 x 7/22 (approx) (pi = 22/7)

r^2 > 280/11

or d^2 > 1120/11

or EC^2 > 1120/11

We know BC = a > EC

For area to be greater than 80,
=> a^2 > EC^2
=> 160 > 1120/11
=> 1760 > 1120 True...

Sufficient.

S2: |BE| > 2

Not sufficient to determine.

Answer: A
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I think the answer is E.

ABC = 45, OD is a tangent, so ODB=90, so BOD=45
OD=R, so BD=R, so BO=R sqrt(2)

Area of triangle ABC

=1/2AC.BC
=0.5(R+Rsqrt(2))^2
=0.5R^2(2.414)^2 =2.9R^2

From 1:
Area of ½ circle = 0.5pi R^2>40
or R^2>80/3.14 ...(1)

Now, we are looking for ABC > 80
or 2.9R^2 > 80
or R^2>80/2.9 (2)

As we can see 1 does not prove 2. INSUFF

From 2:
0.414R>2
R>4.8
R^2 > 23.04
2.9R^2 > 69 max, not 80 hence insuff.

Of course, I may be totally off here, everyone else has a different answer :)
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haas_mba07
Answer: A
For area to be greater than 80,
=> a^2 > EC^2
=> 160 > 1120/11
=> 1760 > 1120 True...


Can u pls explain what u are doing in this step ? IMO this step takes 80 > 40 and then writes this in terms of a and EC and then converts back to numbers to try and prove the assumption. Pls let me know if this is not the case.
IMO that becomes a circular fallacy!! :-)

I have tried by a lengthy geometric analysis to see if area of triangle is greater than 80 based on the first statement and I am not getting a satisfactory answer, i.e. what I am getting is that it may or may not be greater than 80.

In conjunction with st (2) it will become greater than 80.



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