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04 Mar 2011, 08:22
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In an election between two canidates - Lange and Sobel - 70% of the voters voted for Sobel. Of the election`s voters, 60% were male. If 35% of the female voters voted for Lange, what percentage of the male voters voted for Sobel?
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04 Mar 2011, 08:39
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70% voted for Sobel. 30% voted for Lange.
60% male - 40% female
35% of 40% = 40*35/100 = 14% of female voted for Lange. That means; 40-14=26% female voters voted for Sobel.
Total voters voted for Sobel = 70%
26% were female. Then 44% were male.
44% male voted for sobel. Total percentage of voters for Sobel = 60%
44% of 60% = (44/60)*100 \(\approx\) 73.33%
So; 73.33% of male voters voted for Sobel.
Perhaps some mistake; either in my solution or the problem or the options.
60% male - 40% female
35% of 40% = 40*35/100 = 14% of female voted for Lange. That means; 40-14=26% female voters voted for Sobel.
Total voters voted for Sobel = 70%
26% were female. Then 44% were male.
44% male voted for sobel. Total percentage of voters for Sobel = 60%
44% of 60% = (44/60)*100 \(\approx\) 73.33%
So; 73.33% of male voters voted for Sobel.
Perhaps some mistake; either in my solution or the problem or the options.
04 Mar 2011, 11:05
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Official answer is 44%, so it`s correct ... In my opinion the question is not very clear ...
