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Erica has $460 in 5-and 10-dollar bills only. If she has [#permalink]
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28 May 2007, 22:32
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A
B
C
D
E
Difficulty:
25% (medium)
Question Stats:
71% (01:47) correct
29% (01:50) wrong based on 263 sessions
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Erica has $460 in 5-and 10-dollar bills only. If she has fewer 10-than 5-dollar bills, what is the least possible number of 5-dollar bills she could have?
also, C and E won't work b/c when multiplied by 5 they give integer 5 in the units digit. subtracting xx5 from 460 will give you xx5. xx5/10 = integer.5.
Erica has $460 in 5-and 10-dollar bills only. If she has fewer 10-than 5-dollar bills, what is the least possible number of 5-dollar bills she could have? (A) 32 (B) 30 (C) 29 (D) 28 (E) 27
If she had an equal number of each, , she could have 30 of each for a total of $450, and another 2 fivers to make $460. TOTAL = 32. Note that all other choices would give less than $450.
Erica has $460 in 5-and 10-dollar bills only. If she has fewer 10-than 5-dollar bills, what is the least possible number of 5-dollar bills she could have?
(A) 32 (B) 30 (C) 29 (D) 28 (E) 27
Given that: 5x+10y=460 --> 10y=460-5x; x>y --> 10x>10y.
Re: Erica has $460 in 5-and 10-dollar bills only. If she has [#permalink]
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04 Dec 2013, 15:44
OK so there is a 2:1 ratio between 5 and 10 dollar notes. This means that the answer choice can only be even. so that's A, B or D.
Test b: number of 5 dollar notes equal 30. total revenue=150. To make up to 460 total, you need 31 ten dollar notes. Since there is a greater number of $10 dollar notes than $5 dollar notes. Requirement not met. We also know that D is wrong now...as it would give more $10 dollar notes than $5. Therefore A must be the right choice.
Erica has $460 in 5-and 10-dollar bills only. If she has [#permalink]
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10 Aug 2017, 13:59
bmwhype2 wrote:
Erica has $460 in 5-and 10-dollar bills only. If she has fewer 10-than 5-dollar bills, what is the least possible number of 5-dollar bills she could have?
(A) 32 (B) 30 (C) 29 (D) 28 (E) 27
let x=least possible number of fives 5x+10(x-1)=460 x=31.3 5x+10(x-2)=460 x=32 A
Erica has $460 in 5-and 10-dollar bills only. If she has fewer 10-than 5-dollar bills, what is the least possible number of 5-dollar bills she could have?
(A) 32 (B) 30 (C) 29 (D) 28 (E) 27
We can create the following equation in which f = the number of 5-dollar bills and t = the number of 10-dollar bills.
5f + 10t = 460
f + 2t = 92
If the number of 5-dollar bills and the number of 10-dollar bills are equal, i.e., f = t, then we have:
f + 2f = 92
3f = 92
f = 30⅔
Since f, the number of 5-dollar bills, must be a whole number, and f > t, f should be at least 31. Let’s check whether f can be 31t:
If f = 31, then 31 + 2t = 92 → 2t = 61 → t = 30.5. However, t must be whole number also, so f can’t be 31.
Now let’s check if f can be 32:
If f = 32, then 32 + 2t = 92 → 2t = 60 → t = 30. We see that t is a whole number and f > t. So, the least possible value of f is 32.
Answer: A
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71% (01:47) correct
