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siddharthkapoor
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"Tom ended up walking 10% more" could refer to time or distance, as it is new route...
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Tigi75
"Tom ended up walking 10% more" could refer to time or distance, as it is new route...


It says walking 10% more than he usually does, and hence it refers to distance.

If it was, taking 10% more than he usually does, then would have referred to time. (In which case the answer would simply have been 10% increase)

Hope this helps

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siddharthkapoor
Every day, Tom walks from his home to his office, via the same route, covering s feet at a speed of x feet per minute. Today he took a different route and ended up walking 10% more than he usually does, at a speed of x meters per minute. What is the percentage change in the time he took today compared to the time he takes on a usual day? (1 feet = 0.3 meter)

A. 10% decrease
B. 10% increase
C. 67% decrease
D. 67% increase
E. 200% decrease

Old route:

time = distance/rate

time = d/x

New route:

distance = 1.1d

We have to be careful to express the speed in the same unit of measurement:

rate = x m/min = (x m/1 min)(1 ft/0.3 m) = x/0.3 ft/min

time = 1.1d/(x/0.3) = (0.33)(d/x)

new time = (0.33)(old time)

A factor of 0.33 corresponds to a 67% decrease.

Answer: C
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