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Ezekiel went fishing on each day of last week starting on [#permalink]

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02 Jun 2009, 23:05

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Ezekiel went fishing on each day of last week starting on Monday and caught a total of 76 fish. Each day he either caught more or the same number of fish as the day before, and he never caught more than 12 fish in one day. Did Ezekiel catch more than 9 fish on Tuesday?

(1) Ezekiel caught 8 fish on Monday.

(2) Ezekiel caught 4 more fish on Wednesday than he did on Tuesday.
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76-8 = 68.. for maximum fishes to be caught on tuesday.. 6x = 68 ==> x>11.. also, there is a possibility taht he caught only 8 fishes.. 5x = 60 ==> x =10..

2, insufficient..

for maximum fishes to be caught on tuesday .. 0 + x + 5x+20 = 76 => 6x = 56 => x > 9 if the number of fishes caught on monday is more than 2 then X < 9..

Combined...

monday fishes caught = 8.. total remaining is 68

x + 5 ( X+4 ) = 68 6x+20 = 68 6x = 48 x = 6.. maximum caught on tuesday is 6.. hence less than 9..

Try drawing it out on a piece of paper and labelling the days and penciling in the conditions. Try to get arrangements with all the rules... maybe that will help
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1, Mon=8, Tue cannot be 9, because 9+4=13 (but no more than 12 fish per day), Tue must be 9, suff 2. The same logic

Hrm.... What's your logic for (2)?

Logic1: Each day he either caught more or the same number of fish as the day before Logic2: Ezekiel caught 4 more fish on Wednesday than he did on Tuesday Tuesday=x, Wednesday=x+4 and Logic3: he never caught more than 12 fish in one day

Ezekiel went fishing on each day of last week starting on Monday and caught a total of 76 fish. Each day he either caught more or the same number of fish as the day before, and he never caught more than 12 fish in one day. Did Ezekiel catch more than 9 fish on Tuesday?

(1) Ezekiel caught 8 fish on Monday.

(2) Ezekiel caught 4 more fish on Wednesday than he did on Tuesday.

(1) 8 , 8 ,12,12,12,12,12 --> Tue More than 9 fish ? --> No 8 , 10,10,12,12,12,12 --> Tue More than 9 fish ? --> Yes

multiple solutions not sufficient

(2) Max fish caught on any day =12 assume that Wed Ez caught 12 fish .. Tues day Ez caught 8 fish So <9 B is the answer
_________________

Your attitude determines your altitude Smiling wins more friends than frowning

\(A + X + (X + 4) + B + C + D + E = 8 + 8 + (8+4) + 12 + 12 + 12 + 12 = 8 + 8 + 60 = 76\)

So there is only one possible arrangement possible, because if we take anything less than the maximum, the days won't sum to 76 as required in the question.

\(A + X + (X + 4) + B + C + D + E = 8 + 8 + (8+4) + 12 + 12 + 12 + 12 = 8 + 8 + 60 = 76\)

So there is only one possible arrangement possible, because if we take anything less than the maximum, the days won't sum to 76 as required in the question. This is also the same arrangement as in (1).

\(A + X + (X + 4) + B + C + D + E = 8 + 8 + (8+4) + 12 + 12 + 12 + 12 = 8 + 8 + 60 = 76\)

So there is only one possible arrangement possible, because if we take anything less than the maximum, the days won't sum to 76 as required in the question. This is also the same arrangement as in (1).

statement 1 : insufficinet. statement 2 : max fishes caught in a day is 12, that means max fishes that can be caught on tuesday is 8.. hence answer B..