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Please help me to understand what to do to factor this (to get to the last line): \(x^2 y^2\) – xy = 6 given \(x^2 y^2\) – xy – 6 = 0 subtract 6 from both sides ( xy + 2)( xy – 3) = 0 factor
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Please help me to understand what to do to factor this (to get to the last line): \(x^2 y^2\) – xy = 6 given \(x^2 y^2\) – xy – 6 = 0 subtract 6 from both sides ( xy + 2)( xy – 3) = 0 factor
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after the second step rewrite the equation as
\(x^2 y^2\) – 3xy+2xy – 6 = 0 (we get it by factoring)
Please help me to understand what to do to factor this (to get to the last line): \(x^2 y^2\) – xy = 6 given \(x^2 y^2\) – xy – 6 = 0 subtract 6 from both sides ( xy + 2)( xy – 3) = 0 factor
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Do you know how to factor the similar equation:
\(z^2\) – z - 6 = 0
?
When you factor that equation using any method, you end up with (z + 2)(z - 3) = 0.
If so, just think of this equation as being the same exact thing, except instead of z, it has "xy". \(x^2y^2\) is the same thing as \((xy)^2\) after all!
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.