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# Find integers T and R. (1) T!=R (2) R!=T

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SVP
Joined: 03 Feb 2003
Posts: 1603

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Find integers T and R. (1) T!=R (2) R!=T [#permalink]

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17 Aug 2003, 10:34
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Find integers T and R.

(1) T!=R
(2) R!=T

Kudos [?]: 303 [0], given: 0

Manager
Joined: 14 Aug 2003
Posts: 88

Kudos [?]: [0], given: 0

Location: barcelona

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17 Aug 2003, 10:42
T!=R
R!=T=(T!)!=>T=1=>R=1 or T=2=>R=2

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Manager
Joined: 14 Aug 2003
Posts: 88

Kudos [?]: [0], given: 0

Location: barcelona

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17 Aug 2003, 10:42
T!=R
R!=T=(T!)!=>T=1=>R=1 or T=2=>R=2

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Senior Manager
Joined: 22 May 2003
Posts: 328

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Location: Uruguay

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17 Aug 2003, 14:51
So how are we supposed to answer this question? C or E

There are two solutions: R=1;T=1 or R=2;T=2

If we are asked for the value of T and R then the answer is E since we don't have one and only one value for T and R.

If we are asked for the possible numbers of T and R then the answer is C.

Is this correct? Or I'm just complicating things too much and answer is always C?

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Director
Joined: 03 Jul 2003
Posts: 651

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17 Aug 2003, 18:10
In DS questions, it is required to find a unique solution.

Here we have two possible solutions.

So, IMHO, the answer is E.

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Manager
Joined: 10 Jun 2003
Posts: 209

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Location: Maryland

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18 Aug 2003, 11:49
In DS questions, it is required to find a unique solution.

Here we have two possible solutions.

So, IMHO, the answer is E.

If there are two possible values, even when they are combined, then the answer must be E.

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SVP
Joined: 03 Feb 2003
Posts: 1603

Kudos [?]: 303 [0], given: 0

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30 Aug 2003, 23:55
after combining the two sets, we have two pairs: (1, 1) and (2, 2)
Agree, it is E.

Kudos [?]: 303 [0], given: 0

30 Aug 2003, 23:55
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