Find P. (1) |P|P||=3 (2) 2|P|=3

Question

Find P.

(1) |P–|P||=3
(2) 2|P|=3

prashant · Answer

Statement 1 gives the value of P as -3/2

Statement 2 gives values of P as {-3/2, 3/2}

Therefore, statement 1 is sufficient alone to answer the question but statement 2 alone is not sufficient

shevy · Answer

I am getting E

1) 4P^2 = 9 
P = +-3/2

2) P = +-3/2

remgeo · Answer

I am also getting E First eq also gives values of P as +3/2, -3/2. Edit ........ Ok I got it. Silly me .. :wall

It is A.

minu · Answer

I am getting A.

(1) |Pâ€“|P||=3 
if P is +ve then |p-p| = 0 = 3 which makes no sense as 0 != 3
so P must be -ve |-p-p|= 3
-2p = 3 -> p = -2/3 sufficient

(2) 2|P|=3

this means p = +3/2 or -3/2

hence A is suff

remgeo · Answer

Not that it matters in this case, but still.. | -2p | = 3 ie. 2p = 3 ie. p = 3/2. Such mistakes can kill you

Natalya Khimich · Answer

Don't understand why from 1) p can't be +-3/2.

Can somebody explain.

ccax · Answer

Well just plug in numbers. If p>0, then the expression will always be 0.
The graph of |P–|P|| is
-2x, for x<0, and 
0, for x>= 0

Dilshod · Answer

It is A indeed:
The first equation has only one solution –P-P=3P=-3/2

Find P. (1) |P|P||=3 (2) 2|P|=3

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