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06 Mar 2020, 04:56
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
96% (00:58) correct
4%
(01:47)
wrong
based on 90
sessions
History
Date
Time
Result
Not Attempted Yet
Flannery is 28 years old and Harumi is 11 years old. In how many years will Flannery’s age be twice Harumi’s age?
(A) 3
(B) 4
(C) 6
(D) 8
(E) 9
(A) 3
(B) 4
(C) 6
(D) 8
(E) 9
06 Mar 2020, 05:37
Kudos
Bookmarks
Bunuel
Solution:
- • Flannery’s current age = 28 years.
• Harumi’s current age = 11 years.
• Let's assume that after x years, Flannery's age is twice of Harumi's age.
- o \((28 + x) = 2(11 + x)\)
o \(28 + x =22 + 2x\)
o \(28 – 22 = 2x -x\\
\)o \(6 = x\)
ArunSharma12
Joined: 25 Oct 2015
Last visit: 20 Jul 2022
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06 Mar 2020, 05:38
Kudos
Bookmarks
Bunuel
28 + x = 2(11+x)
x =6
Ans: C
