GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 22 Oct 2019, 07:50

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# For all integers m and n, where m ≠ n, m↑n = |(m^2 - n^2)/(m - n)|. Wh

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 58431
For all integers m and n, where m ≠ n, m↑n = |(m^2 - n^2)/(m - n)|. Wh  [#permalink]

### Show Tags

14 Jan 2019, 02:43
00:00

Difficulty:

5% (low)

Question Stats:

97% (00:49) correct 3% (00:59) wrong based on 48 sessions

### HideShow timer Statistics

For all integers m and n, where m ≠ n, $$m↑n = |\frac{m^2 - n^2}{m - n}|$$. What is the value of (–2)↑4?

A. 10
B. 8
C. 6
D. 2
E. 0

_________________
GMAT Club Legend
Joined: 18 Aug 2017
Posts: 5031
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
Re: For all integers m and n, where m ≠ n, m↑n = |(m^2 - n^2)/(m - n)|. Wh  [#permalink]

### Show Tags

14 Jan 2019, 02:52
Bunuel wrote:
For all integers m and n, where m ≠ n, $$m↑n = |\frac{m^2 - n^2}{m - n}|$$. What is the value of (–2)↑4?

A. 10
B. 8
C. 6
D. 2
E. 0

using the expression solve for values of
we would get
2 IMO D
Senior Manager
Joined: 13 Jan 2018
Posts: 342
Location: India
Concentration: Operations, General Management
GMAT 1: 580 Q47 V23
GMAT 2: 640 Q49 V27
GPA: 4
WE: Consulting (Consulting)
Re: For all integers m and n, where m ≠ n, m↑n = |(m^2 - n^2)/(m - n)|. Wh  [#permalink]

### Show Tags

14 Jan 2019, 04:45
m↑n=|$$\frac{m^2−n^2}{m−n}$$|

(–2)↑4 = $$|\frac{(-2)^2 - (4)^2}{-2 - 4}|$$

= $$|\frac{4 - 16}{-6}|$$

= $$|\frac{-12}{-6}|$$

= |-2|

= 2

OPTION: D
_________________
____________________________
Regards,

Chaitanya

+1 Kudos

if you like my explanation!!!
Manager
Joined: 22 May 2017
Posts: 118
Re: For all integers m and n, where m ≠ n, m↑n = |(m^2 - n^2)/(m - n)|. Wh  [#permalink]

### Show Tags

20 Jan 2019, 08:59
simplify the modulus

|(m^2 -n^2) / (m-n)| = |(m+n)(m-n) / m-n| = |m+n| = |-2+4| = |2|
_________________
-------------------------------------------------------------------------------------------------
Don't stop when you are tired , stop when you are DONE .
Director
Joined: 09 Mar 2018
Posts: 994
Location: India
Re: For all integers m and n, where m ≠ n, m↑n = |(m^2 - n^2)/(m - n)|. Wh  [#permalink]

### Show Tags

20 Jan 2019, 09:27
Bunuel wrote:
For all integers m and n, where m ≠ n, $$m↑n = |\frac{m^2 - n^2}{m - n}|$$. What is the value of (–2)↑4?

A. 10
B. 8
C. 6
D. 2
E. 0

Simple expansion of $$m^2 - n^2$$ = (m-n) (m+n), can help us in solving the question

$$m↑n = |\frac{m^2 - n^2}{m - n}|$$

$$m↑n = |\frac{(m-n) (m+n)}{m - n}|$$

$$m↑n = |(m+n)|$$

$$-2 ↑4 = |-2 + 4|$$

_________________
If you notice any discrepancy in my reasoning, please let me know. Lets improve together.

Quote which i can relate to.
Many of life's failures happen with people who do not realize how close they were to success when they gave up.
Re: For all integers m and n, where m ≠ n, m↑n = |(m^2 - n^2)/(m - n)|. Wh   [#permalink] 20 Jan 2019, 09:27
Display posts from previous: Sort by