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08 Sep 2021, 05:00
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
57% (02:29) correct
43%
(02:27)
wrong
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For any integers a, b, c, and d, sechigh(a, b, c, d) is the second highest integer when the integers are placed in an ordered list. For example sechigh(2, 5, 4, 6) = 5 and sechigh(6, 5, 3, 6) = 6 . For the integer y, what is the value of sechigh(6, 7, 11, y)?
(1) y = sechigh (7, 13, 12, x) for some integer x.
(2) y = sechigh (7, 13, 8, z) for some integer z.
(1) y = sechigh (7, 13, 12, x) for some integer x.
(2) y = sechigh (7, 13, 8, z) for some integer z.
08 Sep 2021, 12:29
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Bunuel
Basically, it says that we have a sechigh function that picks the second highest number when the list is ordered.
1)y = second_highest(7, 12, 13, x)
Case1:
x = 13, second highest = 12
Case2:
x = any integer less than or equal to 12, second highest = 12 - Sufficient!
2)y = second_highest(7, 8, 13, z)
Case1:
z = 13, second highest = 8
Case2:
z = 14, second highest = 13 - Insufficient!
IMO, (A)!
25 Sep 2021, 07:17
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Bunuel
The understanding of the sechigh() function is crucial before jumping on the statements. This function returns the 3rd integer from the left or the second highest integer when the integers are sorted in ascending order with the smallest integer positioned at the extreme left.
S1: y = sechigh (7, 13, 12, x) for some integer x [Sufficient]
1. Arranging the terms in ascending order yields 7, 12, 13, x
2. If \(x >= 13\) then the output of the function will be 13 E.g. sechigh(7, 12, 13, 14) \(= 13\) or E.g. sechigh(7, 12, 13, 13) \(= 13\)
3. If \(x < 13\) then the output will be \(12\) E.g. sechigh(7, 12, 12, 13) \(= 12\) or E.g. sechigh(7, 11, 12, 14) \(= 12\)
4. So, we get only two values of \(y\) i.e. \(12\) and \(13\) from this statement
5. Plugging them into sechigh(6, 7, 11, y) we get sechigh(6, 7, 11, 12) \(= 11\) or sechigh(6, 7, 11, 13) \(= 11\)
6. We get a single definitive answer \(11\)
S2: y = sechigh (7, 13, 8, z) for some integer z [Insufficient]
1. Arranging the terms in ascending order yields 7, 8, 13, z
2. If \(x >= 13\) then the output of the function will be \(13\) E.g. sechigh(7, 8, 13, 14) \(= 13\) or E.g. sechigh(7, 12, 13, 13) \(= 13\)
3. If \(x < 13\) then the output can range from \(8\) to \(12\) E.g. sechigh(7, 8, 8, 13) \(= 8\) or E.g. sechigh(7, 8, 12, 13) \(= 12\)
4. So, we get only \(y\) values ranging from \(8\) to \(13\) from this statement
5. Plugging them into sechigh(6, 7, 11, y) we get sechigh(6, 7, 8, 11) \(= 8\) or sechigh(6, 7, 11, 13) \(= 11\)
6. We do not get a single definitive answer
Ans. A
