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\(x_1\): 100
\(x_4\): 25
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
75% (02:23) correct
25%
(02:48)
wrong
based on 1078
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For each positive integer \(i\), the quantity \(x_i\) is defined such that \(x_i = (x_{i+1}) * ( x_{i+2})*2\)
In addition, \(x_3 = 1\). In the table, select values for \(x_1\) and \(x_4\) that are jointly compatible with these conditions. Select only two values, one in each column.
In addition, \(x_3 = 1\). In the table, select values for \(x_1\) and \(x_4\) that are jointly compatible with these conditions. Select only two values, one in each column.
| \(x_1\) | \(x_4\) | Values |
| 2 | ||
| 3 | ||
| 7 | ||
| 10 | ||
| 25 | ||
| 100 |
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Official Answer
\(x_1\): 100
\(x_4\): 25
26 Jul 2014, 09:05
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Hello janxavier,
Let me reword the equation so its a bit easier to read: \(x_i =(x_{i+1}) *(x_{i+2}) * 2\)
Since \(x_1 = x_2 * x_3 * 2\), substitute in \(x_2 = x_3 * x_4 * 2\) yields \(x_1 = x_3 * x_3* x_4 * 4\). Since \(x_3 = 1\), then \(x_1 = x_4 * 4\)
The two values that have a ratio of 1:4 is E & F. I am assuming that \(x_2 = x_4\) in your table, so \(x_1 = 100\) and \(x_1=25\)
Let me reword the equation so its a bit easier to read: \(x_i =(x_{i+1}) *(x_{i+2}) * 2\)
Since \(x_1 = x_2 * x_3 * 2\), substitute in \(x_2 = x_3 * x_4 * 2\) yields \(x_1 = x_3 * x_3* x_4 * 4\). Since \(x_3 = 1\), then \(x_1 = x_4 * 4\)
The two values that have a ratio of 1:4 is E & F. I am assuming that \(x_2 = x_4\) in your table, so \(x_1 = 100\) and \(x_1=25\)
