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For her customer feedback score, Jess wants to average at or above an
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02 May 2016, 01:13
Question Stats:
73% (01:47) correct 27% (01:41) wrong based on 103 sessions
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For her customer feedback score, Jess wants to average at or above an 8.0 rating. For the month of June, she received the following scores: 7, 8, 8, 7, 9, 10, 6, 6, 8 and 7. By what percent did she fall short of her goal? (A) 4% (B) 5% (C) 8% (D) 10% (E) 12%
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Re: For her customer feedback score, Jess wants to average at or above an
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02 May 2016, 05:22
Expected minimum rating = 8
Deviation from the expected minimum rating = (1 + 0 + 0  1 + 1 + 2  2  2 + 0  1)/10 = 4/10 = 0.4
Current rating is 0.4 less than 8.
Percentage = (0.4/8)*100 = 5%
Answer: B



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Re: For her customer feedback score, Jess wants to average at or above an
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10 Dec 2016, 10:22
Great Question. Here is what i did in this Question> Desired Mean => ≥8 Current mean => 7.6 Shortfall => 0.4 So the Question is really asking us "0.4 is what percent of 8" And 0.4 is 5 percent of 8.
Hence B
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Re: For her customer feedback score, Jess wants to average at or above an
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10 Dec 2016, 11:05
Nevernevergiveup wrote: For her customer feedback score, Jess wants to average at or above an 8.0 rating. For the month of June, she received the following scores: 7, 8, 8, 7, 9, 10, 6, 6, 8 and 7. By what percent did she fall short of her goal?
(A) 4% (B) 5% (C) 8% (D) 10% (E) 12% Total score of June is 76 She wants total score of 80 So, She fell short of 4/80*100 = 5% Hence, answer will be (B) 5%
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Re: For her customer feedback score, Jess wants to average at or above an
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13 Apr 2018, 03:44
+1 for B. The trick here is to take differences over 8 and sum them up. Now once you get the net differential , calculate the %
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Re: For her customer feedback score, Jess wants to average at or above an &nbs
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