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For her customer feedback score, Jess wants to average at or above an

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Bunuel
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For her customer feedback score, Jess wants to average at or above an [#permalink] New post  25 Jun 2019, 02:52
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For her customer feedback score, Jess wants to average at or above an 8.0 rating. For the month of June, she received the following scores: 7, 8, 8, 7, 9, 10, 6, 6, 8 and 7. By what percent did she fall short of her goal?

(A) 4%
(B) 5%
(C) 8%
(D) 10%
(E) 12%
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Dillesh4096
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Re: For her customer feedback score, Jess wants to average at or above an [#permalink] New post  25 Jun 2019, 03:05
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Bunuel wrote:
For her customer feedback score, Jess wants to average at or above an 8.0 rating. For the month of June, she received the following scores: 7, 8, 8, 7, 9, 10, 6, 6, 8 and 7. By what percent did she fall short of her goal?

(A) 4%
(B) 5%
(C) 8%
(D) 10%
(E) 12%


Average score received = (6*2 + 7*3 + 8*3 + 9 + 10)/10 = 7.6

% short = % Decrease = 0.4/8*100 = 40/8 = 5%

IMO Option B

Pls Hit Kudos if you like the solution
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MidhilaMohan
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Re: For her customer feedback score, Jess wants to average at or above an [#permalink] New post  25 Jun 2019, 03:10
The total comes out to be 76 and therefore average score= 76/10=7.6
she is short of 4 points and we need to find what percent of 80 is 4 => 5% and thereby Option B
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Lampard42
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Re: For her customer feedback score, Jess wants to average at or above an [#permalink] New post  25 Jun 2019, 07:47
Bunuel wrote:
For her customer feedback score, Jess wants to average at or above an 8.0 rating. For the month of June, she received the following scores: 7, 8, 8, 7, 9, 10, 6, 6, 8 and 7. By what percent did she fall short of her goal?

(A) 4%
(B) 5%
(C) 8%
(D) 10%
(E) 12%


Average = (8*3+7*3+6*2+19)/10=7.6

Short by .4 so .4*100/8 = 5% IMO B
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Re: For her customer feedback score, Jess wants to average at or above an [#permalink] New post  26 Jun 2019, 02:49
Bunuel wrote:
For her customer feedback score, Jess wants to average at or above an 8.0 rating. For the month of June, she received the following scores: 7, 8, 8, 7, 9, 10, 6, 6, 8 and 7. By what percent did she fall short of her goal?

(A) 4%
(B) 5%
(C) 8%
(D) 10%
(E) 12%


total sum = 76 ; avg ; 7.6
fell short of 8-7.6; .4
so .4/8 * 100 ; 5%
IMO B
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ScottTargetTestPrep
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Re: For her customer feedback score, Jess wants to average at or above an [#permalink] New post  01 Jul 2019, 18:00
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Bunuel wrote:
For her customer feedback score, Jess wants to average at or above an 8.0 rating. For the month of June, she received the following scores: 7, 8, 8, 7, 9, 10, 6, 6, 8 and 7. By what percent did she fall short of her goal?

(A) 4%
(B) 5%
(C) 8%
(D) 10%
(E) 12%



Jess’ average in June is:

(6 x 2 + 7 x 3 + 8 x 3 + 9 + 10)/10 = (12 + 21 + 24 + 19)/10 = 7.6

The percent difference is:

(8 - 7.6)/8 x 100 = 0.4/8 x 100 = 0.05 x 100 = 5%

Answer: B
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Re: For her customer feedback score, Jess wants to average at or above an [#permalink] New post  15 Dec 2021, 03:07
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: For her customer feedback score, Jess wants to average at or above an [#permalink]
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