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| Last visit was: 03 Sep 2026, 22:40 |
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Difficulty:
Question Stats:
75% (00:43) correct
25%
(00:45)
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based on 876
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| As we have |a| in the equation so we will have two cases | |
| -Case 1: a ≥ 0 => |a| = a => 2 < a < 9 => Possible integer values of a are from 3 to 8 => (8-3) + 1 => 6 values | -Case 2: a ≤ 0 => |a| = -a => 2 < -a < 9 Multiplying with -1 on all the sides and changing the sign of the inequality => -2 > a > -9 => -9 < a < -2 => Possible integer values of a are from -8 to -3 => 6 values |
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