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vix
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I think I was thinking completely off-track! Thanks for the reply @Gyanone!
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Also, about your second question:
2^n = n^2 will be satisfied by 2 integers
3^n = n^3 will be satisfied by just one integer
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Only possible values are -1, 0 , 1

Try -1: 1^-1 = 1/1^1 = 1 and -1^1 = -1 so no.
Try 0 : 1^0 = 1 and 0^1 = 0 so no.
Try 1: 1^1= 1 and 1^1 = 1. This is right. Answer B.
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vix
For how many integers n is 1^n = n^1?

A. none
B. 1
C. 2
D. 3
E. More than 3

My answer was d. 3 because:

1^0 = 0^1 = 1
1^-1 = -1^1
and 1^1 = 1^1

Hence we have 3 integers for this, but the answer was given as b. 1 saying that 1^1 = 1^1 (n=1).

Similar question to practice: for-how-many-integers-n-is-2-n-n-101911.html
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vix
For how many integers n is 1^n = n^1?

A. none
B. 1
C. 2
D. 3
E. More than 3


Since 1^n always equals 1, we need to determine the number of values of n such that n^1 will equal 1. The only way for n^1 = 1, is when n = 1.

Answer: B
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